| To: | Andy Talbot <[email protected]> |
|---|---|
| Subject: | Re: LF: TXing 2200m WSPR |
| From: | Chris Wilson <[email protected]> |
| Date: | Sun, 24 Dec 2017 23:03:51 +0000 |
| Cc: | [email protected] |
| Dkim-signature: | v=1; a=rsa-sha256; c=relaxed/relaxed; d=gmail.com; s=20161025; h=date:from:message-id:to:cc:subject:in-reply-to:references :mime-version:content-transfer-encoding; bh=/70mi0nwiLWuT6MoWmAp0KH7zhhxa2Jy02Kh2qDt5ic=; b=TNAXqYlLvpkblsmLTiGYCmgC0uovfIldEQFXH3Ro+46uDd2wRC7kCpMMoo791bp4mP 7gdXymI+mU3g4qO283RklhQAfn5hkGGaUxzytPqcJByLCntJpy32QOWWmRE3dBQVdBKV A8UFSzHqEX8mpR5SmrjMQ5ILwoBO9P7ZYNy/iGpUuvxezs07PsTJV0c79tMqyuZa5+JM 4bXkyja+ONkdnkUbpUQnx5YBxaYKH6N4ZbNw9UfFZc5ivFKJzhxP9k+5cKAtw6n1Cd3w IWVQsc1d0bz4xaLxDnESKqECYOy5Qlpr9ugMR89McMrTfXBZvoYFTcGE9M58ZSvk726F 2x8w== |
| In-reply-to: | <CAA8k23RMPWcJBhnE0qK+b=sP7kQpPCBO3t8LgKHTij-4xtud-g@mail.gmail.com> |
| References: | <[email protected]> <[email protected]> <[email protected]> <[email protected]> <[email protected]> <[email protected]> <[email protected]> <[email protected]> <[email protected]> <103A2C60B87B4930A99ED33442E477AF@StevePC> <[email protected]> <[email protected]> <CANA3B6WiCbKZmP_hA-gyunrx-NVT=mHyT9Sq6Fgu7fE-yx3QQA@mail.gmail.com> <CAA8k23Qb+-82S0WySY4bXY7+bZOnKorHtdG-qOXkafUBs873=Q@mail.gmail.com> <[email protected]> <CAA8k23TnyE0NUGA9XQsmDhOxn81dqNTC3pQh2H7VfEoQHH=mXw@mail.gmail.com> <[email protected]> <CAA8k23RMPWcJBhnE0qK+b=sP7kQpPCBO3t8LgKHTij-4xtud-g@mail.gmail.com> |
| Reply-to: | [email protected] |
| Sender: | [email protected] |
Hello Andy,
Is there any point in Paul putting his dummy load on the end of his
75 odd meters of feeder co-ax outside? And then on the secondary of
his matching transformer when tapped one to one? In case the co-ax is
iffy or the impedance matching transfomer's doing something odd?
Sunday, December 24, 2017, 10:42:16 PM, you wrote:
> Well ... Using exactly the values in the filter circuit diagram,
> 50R transforms through the filter to 48.5 - j2.86 (Ret Loss = 30dB,
> VSWR = 1.07) [Using GM3SEK's original Netcalc prog.]
> So that's pretty conclusive the ideal filter values will not be
> upsetting things at the fundamental frequency.
> According to Google, the T106-2 has a stated Al value of 13.5nH
> /turn^2 so 72 turns does indeed give 70uH. So IF your core is correct, the
> filter should be OK.
> It's a bit difficult from now on, at a distance, to try to work out what is
> happening.
> Anyone else, any suggestions ?
> BTW ...
> Peak to peak of a { symetrical }square wave needs to be multiplied
> by 4/pi to get the peak-to-peak of the fundamental component. So
> the amploitude you see will be lower by about 1.3 times for teh same
> fundamental power component.
> Andy G4JNT
--
Best regards,
Chris mailto:[email protected]
|
| <Prev in Thread] | Current Thread | [Next in Thread> |
|---|---|---|
| ||
| Previous by Date: | Re: LF: TXing 2200m WSPR, Andy Talbot |
|---|---|
| Next by Date: | Re: LF: TXing 2200m WSPR, N1BUG |
| Previous by Thread: | Re: LF: TXing 2200m WSPR, Andy Talbot |
| Next by Thread: | Re: LF: TXing 2200m WSPR, Andy Talbot |
| Indexes: | [Date] [Thread] [Top] [All Lists] |