To: | [email protected] |
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Subject: | Re: LF: A transductor for power regulation? |
From: | Andy Talbot <[email protected]> |
Date: | Wed, 19 Apr 2017 12:59:30 +0100 |
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The easiest way to think of a transformer , I believe, is to accept it has "infinite" (oar at least arbitrarily high) inductive reactance, and that part of it can be ignored. So an open circuit on the secondary is transformed to an open circuit on the secondary; ditto a short circuit. And any impedance by N squared. A practical "very high" Xl is ensured by using high Ue ferrite, and using enough turns that your ferrite is not degraded by saturation.
As soon as that "infinite" inductance begins to drop, it appears in parallel with the pri / sec and contributes to the transformed load impedance. Which lowers it with shunt inductive reactance. Even worse is when the ferrite is driven into saturation, and the AC component drives it around the B-H hysteresis curve. This dissipates energy in the core, and dissipated energy appears [electrically] to be added resistance. Whether it appears in parallel or in series is moot; it is there, and dissipating. A tapped inductor, or two coupled inductors may have an incidental impedance transforming action , but if the inductance, or Xl, is significant and enters the matching or load impedances - it is NOT a transformer It is a pity that transformers and inductors both have the same circuit symbols, and similar wound construction in some cases. So trying to control a transformer with DC saturation is very definitely not on. But controlling a saturable inductor very definitely is acceptable. If that inductor happens to be part of a matching network, or be tapped, or have two windings - you have to study , calculate and think what it is going to actually do Andy G4JNT On 19 April 2017 at 09:41, DK7FC <[email protected]> wrote:
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