To: | [email protected] |
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Subject: | Re: LF: A transductor for power regulation? |
From: | Markus Vester <[email protected]> |
Date: | Wed, 19 Apr 2017 06:41:44 -0400 |
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Hi Stefan,
I think you'd have to do it the other way round, i.e. place the saturable reactor in series with the load. Without DC, the reactor will present high impedance, minimizing RF and supply current. You could use a small parallel C to tune out the large inductance. Increasing the DC current will reduce the transductor impedance and increase the output. Higher biasing will reduce the available B swing and voltage drop. At maximum output, you could then compensate the remaining stray inductance by a series C, or a slightly off resonant antenna. Best 73, Markus -----Ursprüngliche Mitteilung----- Von: DK7FC <[email protected]> An: rsgb_lf_group <[email protected]> Verschickt: Mi, 19. Apr 2017 10:42 Betreff: Re: LF: A transductor for power regulation?
Hi Andy,
Yes yes, i agree, and that's what i don't fully understand yet. Last night i played a bit with the transductor that is laying arround here in a cupboard. It didn't take much time to build up a 1:1 transformer. I took my small MF PA and a 50 Ohm dummy load. I watched the sine wave across the R with a scope. About 50W were passed through the transformer. Then i started to run a DC current into the saturating coil. The amplitude on the dummy load decreased but the PA consumed even more current! Not a good working point. But then, how is this transformer working? It looks like it can only work in a series resonant circuit, as you say. So it is not really a transfromer. Actually i built something similar a few months ago, when i wanted to increase the resonance frequency of a HV mains transformer (antenna C = 480 pF switche in parallel to the HV winding). The idea was to saturate the two outher legs of the tripple leg transformer which has its windings on the center leg... 73, Stefan Am 19.04.2017 08:59, schrieb Andy Talbot:
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