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RE: ULF: A new step on the large ULF coil...

To: "[email protected]" <[email protected]>
Subject: RE: ULF: A new step on the large ULF coil...
From: VIGILANT Luis Fernández <[email protected]>
Date: Fri, 28 Oct 2016 09:27:46 +0000
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Thread-topic: ULF: A new step on the large ULF coil...
Hi Stefan ....xLF !! :-)
 
That's the long explanation I needed to get it clear. Thank you very much !
 
 
73 de Luis
EA5DOM


De: [email protected] [mailto:[email protected]] En nombre de DK7FC
Enviado el: jueves, 27 de octubre de 2016 12:28
Para: [email protected]
Asunto: Re: ULF: A new step on the large ULF coil...

Hi Luis,

Am 27.10.2016 11:40, schrieb VIGILANT Luis Fernández:
Amazing work Stefan !! :-O
 
I bet you have constructed some kind of support (like a lathe) which lets you rotate the pipe easily and wound the coils . Right ?
Right! See: https://dl.dropboxusercontent.com/u/19882028/ULF/20160702_222257.mp4
It's quite comfortable but still a lot of work.
This is getting really heavy and the quality of coils looks very nice and repeteable ...... at least five times ! ;-)
5 kg of copper wire so far. Still quite managable.
 
Dumb question: Why do you get different inductance values when resonating it with antenna equivalent capacitor and when measuring current at 273V AC / 50Hz  ??
Shouldn't be inductance a constant value ? ...... or I'm missing something obvious :(
It's due to the inner-winding capacity which is higher than on a single layer coil. At the self-resonance frequency you need no external C to get this resonance, of course. Then add just 10 pF external C. The new resonance frequency will be almost the same. If you calculate L from that frequency and C, it will be a gigantic high value, several GH :-)
Assume the internal C is 100 pF. And L is 4 H. Then f res will be about 7.9577 kHz. With 10 pF external it will be 7.5874 kHz. If you ignore the internal C and say "I'm getting 7.5874 kHz with just 10 pF connected to the L" you would calculate L = 44 H!
So you need to switch a much larger C in parallel to L so that the internal C becomes irrelevant. Maybe 1 uF, then you will get 79.6 Hz at 4H. When calculating L with 1.000001 uF (1uF + 100 pF) and 79.6 Hz you will get 3.997 H, which is quite correct!
It doesn't need to be a resonated circuit of course. You can also apply a constant voltage and simply measure the current. But you need to know the DC resistance then. Then Z = U/I = R^2 + XL^2 and L = XL / 314 (at 50 Hz).

 
Good luck with the 6th floor. Seems that there is no room for a 7th, so that's why you mentioned the variometer
I will first build the variometer now on a 16cm diameter and 6cm high piece of tube. Will see what the tuning range is. You know, actually i'm not a friend of calculations if i can do an experiment instead :-)

73, Stefan
 
73 de Luis
EA5DOM


De: [email protected] [mailto:[email protected]] En nombre de DK7FC
Enviado el: miércoles, 26 de octubre de 2016 19:06
Para: [email protected]
Asunto: Re: ULF: A new step on the large ULF coil...

Hi ULF,

It's just a few weeks ago, now the 5th stack is wound on the coil: https://dl.dropboxusercontent.com/u/19882028/ULF/20161026_185804.jpg

The DC resistance rose from 445 Ohm to 572 Ohm.
The measured resonance frequency (using the antenna equivalent C in the shack) dropped from 3.667 kHz down to 3.208 kHz. That should be about 4.92 H.
Measured at 273V AC / 50 Hz, i'm getting 197 mA, so the actual inductance is 4.0 H.

A 6th stack and a variometer part is needed!

73, Stefan

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