Pat,

   "There is a theory which states that if ever anyone discovers exactly what the Universe is for and why it is here, it will instantly disappear and be replaced by something even more bizarre and inexplicable. There is another theory which states that this has already happened."

-Douglas Adams

On Wed, Jul 10, 2013 at 2:53 PM, pat <[email protected]> wrote:

Of course, it also holds to be true that the "rest of the universe" that is the "other plate" of my capacitor is also the "other plate" of everyone else's similar capacitor and is the common circuit element to which we are all referenced!

73

On 10/07/13 18:30, Pieter-Tjerk de Boer wrote:

On Wed, Jul 10, 2013 at 05:58:44PM +1000, edgar wrote:

Surely every conductor in the unit will have a difference in potential
due to being in a electromagnetic field.
Even in the legs of the FET. Although the potential will be extremely small.

Yes, of course that's correct.

I should have written that with a fiber optic cable instead of the coaxial
cable, all circuit elements are coupled to the field at _almost_ the same
place, and thus are at _almost_ the same potential, and thus _almost_ no
signal will come out: very much less than with the coax still in place.

B.t.w., some mini-whips are built using a metal can as the probe, with
the entire electronics inside the can; such an arrangement would get
quite close to zero output when the coax is replaced by the fiber optics.

Anyway, it was originally claimed that the functioning of the mini-whip
does not depend on the coaxial cable; I just intended to explain why I
think it does.

73, Pieter-Tjerk, PA3FWM

--
73 de pat g4gvw
es gd dx
qth nr Felixstowe
East Coast UK

--
73 Warren K2ORS
                WD2XGJ
                WD2XSH/23
                WE2XEB/2
                WE2XGR/1

 

-- 
73 de pat g4gvw
es gd dx
qth nr Felixstowe
East Coast UK