To: | rsgb_lf_group@blacksheep.org |
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Subject: | Re: Fwd: Re: LF: VK1OD's analysis of the MiniWhip antenna |
From: | Pieter-Tjerk de Boer <ptdeboer@cs.utwente.nl> |
Date: | Wed, 10 Jul 2013 19:30:20 +0200 |
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On Wed, Jul 10, 2013 at 05:58:44PM +1000, edgar wrote: > Surely every conductor in the unit will have a difference in potential > due to being in a electromagnetic field. > Even in the legs of the FET. Although the potential will be extremely small. Yes, of course that's correct. I should have written that with a fiber optic cable instead of the coaxial cable, all circuit elements are coupled to the field at _almost_ the same place, and thus are at _almost_ the same potential, and thus _almost_ no signal will come out: very much less than with the coax still in place. B.t.w., some mini-whips are built using a metal can as the probe, with the entire electronics inside the can; such an arrangement would get quite close to zero output when the coax is replaced by the fiber optics. Anyway, it was originally claimed that the functioning of the mini-whip does not depend on the coaxial cable; I just intended to explain why I think it does. 73, Pieter-Tjerk, PA3FWM |
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