To: | <[email protected]> |
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Subject: | AW: LF: Re: 9 kcs |
From: | Stefan Schäfer <[email protected]> |
Date: | Sun, 6 Jun 2010 21:26:42 +0200 |
References: | <004801cb04d6$e9740b80$0401a8c0@xphd97xgq27nyf> <CD190EC05BA84C1685A9A2F4A56DD284@JimPC> <001101cb054f$49a29c60$0401a8c0@xphd97xgq27nyf> <52F731AEBF244DE99A2D6D5162CE2296@JimPC> <[email protected]> <002301cb05a6$4a0172b0$0401a8c0@xphd97xgq27nyf> |
Reply-to: | [email protected] |
Sender: | [email protected] |
Thread-index: | AcsFpuO1qufGuLtfQh+dt/AxggNbFgABk20m |
Thread-topic: | LF: Re: 9 kcs |
Mal wrote: >It is easy to generate a 9 kcs signal and high power audio amplifiers are >plentiful to radiate several K/watts to a loaded inverted L 20 + metres >high. You should take that "/" and place it between "kc" and "s"! Than both units would be written correctly: kc/s (= kHz) and kW! It's so easy! Or have you meant Kelvin per watt? Stefan/DK7FC <<winmail.dat>> |
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