Hi Andy, IMO, you are being too much of a perfectionist to worry about sin(x)/x. I believe that x must be pi * fsig / fsample, because the spectrum goes to zero at multiples of fsample. So at 20 kHz
Hi Rik and all, Many words ending in -ize (American), have a preferred spelling -ise in British English. http://www.bartleby.com/68/45/5645.html http://www.geocities.com/CapitolHill/Lobby/6524/spelli
Hi Alan, Sorry for the slow reply; I was waiting for responses to see what hardware locking ability potential users already had. All but one had the ability to drive their receiver's reference from a
Hi all, I am working on a new version of WOLF, which will feature frequency and message timing synchronized to UTC, as well as real-time transmission and reception via a sound card. The raw data rate
Hi Alan, First, my apologies for taking so long to answer. Second, my apologies for not understanding what you meant by 'keyed oscillator'. I think that the LC oscillator has to be quite stable, unle
Hi Alberto, The filtering requirements are less onerous if the dithering frequency components are maximized, e.g. by a DDA algorithm. In Johan's example, add 442 to a variable each main PWM cycle. If
Hi Alberto, The new site is awesome! From here in Reno, Nevada (near the US west coast), one can download the larger files at > 250 kilobytes / sec. This compares with about 4.4 kilobytes / sec. from
Mike, We can see your home page at http://www.apersonalguide.co.uk/lf/lftoday/ , but most of the links are bad. The problem is not obvious from your own machine, because they point to e.g. My Documen
Hi Walter and all, This is more complex than it appears. Yes, the series of 8 pulses only lasts 8 mS Well, on a master station, there is a ninth pulse with an extra millisecond gap, so you would need
Not true. For example, if you have a 100 watt CW transmitter with the key held down, the carrier power is 100 watts. Now, what happens when you send a string of dots (50% duty)? Your total power out
For a dot lasting an hour, followed by a space lasting an hour and then repeated, the total power is 50 Watts, with 25W in the carrier, and the rest in the entire set of sidebands stretching out to i
Hi Alberto, One possible problem is that the ratio of peak to average power is very high. For example, if you had 64 carriers of one watt each, the average power would be 64 watts, but you'd need (in
Hi, You may wish to consider a dual 4-input analog mux such as the '4052. For instance, see http://www.semiconductors.philips.com/pip/74HC4052.html You can connect the quadrature LO outputs directly
Hi Wolf, Well, it's not really avoiding the audio phase shift -- the 90 deg. shift is still being done by your software, and the 180 deg. shift is being done by taking the mux outputs differentially.
http://www.megapulse.com/chaininfo.html You may be interested in 6731 Lessay 7001 Bo 7499 Sylt 9007 Eidi 73, Stewart KK7KA This request came up on another list that I'm on and I feel sure that someon
TA enthusiasts Only signal visible last night was DRP...don't think anyone else was transmitting. Traces of DRP visible starting 2300Z through fadeout at 0730Z. Best capture of the session below. Jay
Hi Wolf and all, I just posted a copy of the WOLF sources at http://www.scgroup.com/ham/wolf-source.zip This has the complete environment; if you have MS VC++ you should be able to build it right awa
Hi Mike and all, By the sounds of what you wrote, WOLF could become the mode of choice for crossing the pond with a Part 15 signal level. I'd very much like to see that happen, but ... If we had cond
Hi Markus and all, WOLF keeps an array of "reference match power" values for each possible frame offset and frequency. The highest value in this array is displayed as "pm", and its index is used to a
Hi Markus and all, Does that mean you have to do two million 960-point correlations per receive block to fill it? No, the complex baseband signal is "despread" in 960 positions by multiplying by the
