To: | Andy Talbot <[email protected]> |
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Subject: | Re[2]: LF: Protecting a MOSFET driver chip from MOSFET failure? |
From: | Chris Wilson <[email protected]> |
Date: | Mon, 10 Aug 2015 16:28:53 +0100 |
In-reply-to: | <CAA8k23S6O1-cw6TJ=+=4GTh2iPG=GY1nb9xXyg903fuYG62t9A@mail.gmail.com> |
Organization: | Gatesgarth Developments |
References: | <[email protected]> <CAA8k23SH41BrC=+NTy7PicsO+9giz+mwN5yYF7Ckg8bMsNZe0A@mail.gmail.com> <CAA8k23RzcYO9Y8=1_ZrUDYA0NH=XWBeSqtaZriyzR=En0Ag-sg@mail.gmail.com> <7E7DFBB4D102A04DB5ADC88D66628A4A443E0BC1@ICTS-S-MBX1.luna.kuleuven.be> <CAA8k23S6O1-cw6TJ=+=4GTh2iPG=GY1nb9xXyg903fuYG62t9A@mail.gmail.com> |
Reply-to: | [email protected] |
Sender: | [email protected] |
Hello Andy, Monday, August 10, 2015 > No, capacitive coupling with diode restorationends up with > near-enough the same voltage applied to the gate as you had in thr first > place. > A 0/12v output from the driver chips ends up at -0.7 /+ 11.3 V (assuming 0.7V > diode drop) > As for the question of the dual drive with resistors. The > resistors may as well say in, just to smooth off edges and reduce > dissipation in the driver. i doubt you'll notice any difference. > Andy G4JNT OK, thanks and sorry for the naive questions, lots to learn, I was amused by my friend calling power FET's "Fire Emitting Transistors". I see his point now, they do go with a good bang and sizzle! The wife smelt them downstairs and asked wearily if it meant a longer wait before a job she attached great importance to, but I classed as a boring irrelevance, got done... -- Best regards, Chris mailto:[email protected] |
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