To: | [email protected] |
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Subject: | LF: Horizontally polarised radiation |
From: | "Dick Rollema" <[email protected]> |
Date: | Mon, 05 Jan 2004 17:47:50 +0100 |
In-reply-to: | <000201c3d2f3$c4fb5f40$61e4fc3e@l8p8y6> |
References: | <[email protected]> <000001c3d009$acf7a620$c7e47f50@Smisan> <[email protected]> <000601c3d2c3$2bd34e70$b733f7c2@johnb5a82ea1a4> <[email protected]> <000201c3d2f3$c4fb5f40$61e4fc3e@l8p8y6> |
Reply-to: | [email protected] |
Sender: | <[email protected]> |
To All from PA0SE, In an earlier e-mail I wrote: Mal, G3KEV commented: What I said was that the radiation from the horizontal part of a top loaded aerial is largely absorbed in the earth under it because the wire is so near to the surface. To have a closer look I modeled a 40m long dipole for 136kHz, made of 1.5mm copper wire over real ground at a height h. Ground constants are dielectric constant 13; conductivity 5mS/m. The simulation shows that the maximum of radiation is under an elevation of 90 degrees. The gain is referenced to a half wave dipole in free space. h in metres gain in dBd 500 -2.29 200 -6.65 100 -11.84 50 -17.44 20 -25.40 10 -31.48 The numbers speak for themselves. The radiation by the vertical part of the aerial, that does the work, is not affected by this of course. 73, Dick, PA0SE |
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