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| To: | "[email protected]" <[email protected]> |
|---|---|
| Subject: | RE: LF: EbNaut at 8270.01953125 |
| From: | Jacek Lipkowski <[email protected]> |
| Date: | Tue, 9 Jan 2018 17:32:19 +0100 (CET) |
| In-reply-to: | <AB5C5F55D39BBF46BA47A2A4375A0C4501D2A415CB@PLNWPVEXMB01.ad.corp.globalstar.com> |
| References: | <CANA3B6XjBJvarmGZXwNrMFXdZN5Vb7mQmTWPV41zT7DEfw5RtQ@mail.gmail.com> <[email protected]> <CANA3B6WbU6DQ+Ga8HVdtzQQa4sNQHpj+afFvJ8VvgeVQJCVYKA@mail.gmail.com> <[email protected]> <CANA3B6VCdJbmto-DMgyTX+NC7u_pxnzUE9X16ADFDvOy6tETsw@mail.gmail.com> <[email protected]> <AB5C5F55D39BBF46BA47A2A4375A0C4501D2A415CB@PLNWPVEXMB01.ad.corp.globalstar.com> |
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| User-agent: | Alpine 2.11 (DEB 23 2013-08-11) |
On Tue, 9 Jan 2018, David Weinreich wrote: My question is how long does it take to measure 8270.01953125 Hz? Based on my experience, it seems that it would take more than 3 years. Where am I going wrong. consider a "hardware" example:you can do the stuff that most frequency counters do: they have two inputs: a slow reference clock (like 1Hz, which gives 1Hz measurement resolution), and the measured frequency input. you count the number of input cycles every reference clock pulse. to correctly measure 8270.01953125 Hz you need a 0.00000001 Hz reference (which is one cycle per 100000000 seconds, or 3.17 years). but you can do it the other way, just exchange the frequency counter inputs: have a fast reference clock, and count the number of the reference cycles every input frequency cycle. this way the measurement takes one input cycle (1/8270 seconds), the faster the reference clock, the more resolution you have. VY 73 Jacek / SQ5BPF |
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