Return to KLUBNL.PL main page

rsgb_lf_group
[Top] [All Lists]

Re: VLF: Transatlantic success East to West - nonreciprocity

To: [email protected]
Subject: Re: VLF: Transatlantic success East to West - nonreciprocity
From: Markus Vester <[email protected]>
Date: Mon, 11 Dec 2017 06:51:57 -0500
Cc: [email protected]
Dkim-signature: v=1; a=rsa-sha256; c=relaxed/relaxed; d=mx.aol.com; s=20150623; t=1512993119; bh=PDMhyUvIU99Yd+wkursAlPBP0PKeSjx8bcdx4hU8LRA=; h=From:To:Subject:Message-Id:Date:MIME-Version:Content-Type; b=dRU9YqIEwLzb3S3uxOs41f1gfq3dYbdpGBUkxbQ93cx62fbIXlsJict4MM94CIgDf xGLdFfwQVznAhNVCRDMcti8JmORRbuUL4HULyCIbXX+WMW5hv5lHmOJu6QFdlWnZCB VRL9ptBz/JBON0551WiRAiUJ9jNO6qQ7Z1mLHzs0=
In-reply-to: <[email protected]>
Reply-to: [email protected]
Sender: [email protected]
I've also been looking for a simple and intuitive explanation, without luck so far. 

Maybe a plausible approach is thinking of Hall conductivity in the lower ionosphere, which would tilt the current density (i.e. the source of the reflected field, blue) versus the impinging electric field (red). The vertical tilt angle (upwards or downwards) depends on the horizontal component of Earth's magnetic field (green). So for a west-to-east path, I speculate that the source dipoles may be tilted downwards, and better radiate in the direction of the outgoing wave.

73, Markus (DF6NM)



-----Ursprüngliche Mitteilung-----
Von: Paul Nicholson <[email protected]>
An: rsgb_lf_group <[email protected]>
Cc: Michael Smith <[email protected]>
Verschickt: Mo, 11. Dez 2017 11:43
Betreff: Re: VLF: Transatlantic success East to West


Jacek wrote:

> could you give a short explanation? i don't really understand
> nonreciprocal propagation

I don't either, really. The ionospheric reflection
coefficient depends on the direction of the radio wave relative
to the Earth's magnetic field. The wave accelerates free
electrons in the plasma, and they're pulled into circular or
helical paths by the magnetic field. This alters the phase of
the reflection and the attenuation of the wave through energy
loss by collisions.

The consequence is the reflection coefficient isn't a nice
simple number, it's a 2x2 matrix with each component a
(frequency dependent) complex number.

It's all the in Appleton-Hartree equations

https://en.wikipedia.org/wiki/Appleton%E2%80%93Hartree_equation

which are quite easy to calculate and program (easier than
they look at first glance) but few people would admit to
understanding them.

Spent some time with LWPC measuring the T/A path at some
different frequencies. The figures below are the extra loss
on the east-to-west, compared with west-to-east.

The results don't depend much on which end points I choose,
but are quite frequency dependent:

Midnight UTC:

18.0 kHz: 2 dB
17.4 kHz: 3 dB
16.5 kHz: 6 dB
16.0 kHz: 9 dB
15.0 kHz: 14 dB
14.0 kHz: 18 dB
13.0 kHz: 16 dB
12.0 kHz: 13 dB
11.0 kHz: 11 dB
10.0 kHz: 10 dB
9.0 kHz: 10 dB
8.2 kHz: 12 dB
5.2 kHz: 27 dB
4.2 kHz: 44 dB
2.9 kHz: LWPC doesn't run

Generally a lot more anisotropy as the frequency drops,
but there's a funny peak around 14 kHz.

Midday UTC:

18.0 kHz: 4 dB
17.4 kHz: 4 dB
16.0 kHz: 5 dB
15.0 kHz: 5 dB
14.0 kHz: 6 dB
13.0 kHz: 7 dB
12.0 kHz: 8 dB
11.0 kHz: 9 dB
10.0 kHz: 10 dB
9.0 kHz: 12 dB
8.2 kHz: 14 dB
5.2 kHz: 35 dB
4.2 kHz: no output from LWPC

The funny peak vanishes during the day.

So, nowhere near as much anisotropy as I thought at
17.4 kHz. I don't fancy our chances at the lower
VLF bands - it might be easier to take the long path!

--
Paul Nicholson
--

Attachment: Hall_angle.jpg
Description: JPEG image

<Prev in Thread] Current Thread [Next in Thread>