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| To: | [email protected] |
|---|---|
| Subject: | Re: LF: Re: how to increase the Q of my loading coil? |
| From: | Stefan Schäfer <[email protected]> |
| Date: | Sat, 16 Feb 2013 22:11:12 +0100 |
| In-reply-to: | <E2FD3CEF9D874A728D06769DF8C30AEA@Clemens0811> |
| References: | <CAKvcm2dbFX3d+jv04M_quU0Nwy=W-g5Jk5vxcN5SP87gg3PmzA@mail.gmail.com> <B507F4F2886F4488A919515FDD664BC3@gnat> <B4BD637350C7488DA8A8BAF58FC09D7D@AGB> <E2FD3CEF9D874A728D06769DF8C30AEA@Clemens0811> |
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Am 16.02.2013 11:10, schrieb Clemens Paul: [...] The higher the *loaded circuit* Q the higher are the losses in all involved components including the coil due to increasing circulating currents. Given a certain circuit increasing the Q of its components always will reduce overall losses of that circuit. 73 Clemens DL4RAJ ...however if the transmit power is kept constant, then the radiated power is higher, due to the higher currents through the radiation resistance. Thus the losses must be lower here. It is not a constant voltage source, at least Dimitris' class E PA isn't :-) So a high Q must be the goal, loaded or unloaded. 73, Stefan/DK7FC |
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