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LF: RE: DLF passive received with earth antenna

To: <[email protected]>
Subject: LF: RE: DLF passive received with earth antenna
From: "James Moritz" <[email protected]>
Date: Sat, 17 Jul 2010 22:43:10 +0100
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Dear Stefan, LF Group,

It gets confusing when the bandwidth changes! In this case, both measurement bandwidths are much smaller than the modulation bandwidth, and the signal has a continuous spectrum, so it is reasonable to assume the measured signal power will be proportional to the measurement bandwidth. The amplitude of the signal on the earth antenna was -20dB in 3Hz BW. To normalise the measurements to a 3Hz FFT BW, you need to add 6dB to the amplitude of the 1m^2 loop signal in 0.75Hz bandwidth, to give -94dB as you said. The ratio of signal amplitudes is then 74dB, or a factor of about 5000. So the eqiuvalent area of the earth antenna is 5000m^2.

Adding Markus' factor of 11dB to give the total signal amplitude from the 1m^2 loop gives -83dB, 74 dB below your reference level of 44mV = -9dB. Therefore the 1m^2 loop EMF is about 9uV, corresponding to FS of DHO38 being about 18mV/m. If this is correct, it corresponds to about 1.1MW ERP, which is impressive, but since the signal is down in the noise in your system, these figures can only be a very rough estimate.

Cheers, Jim Moritz
73 de M0BMU

----- Original Message ----- From: "Stefan Schäfer" <[email protected]>
To: <[email protected]>
Sent: Friday, July 16, 2010 11:32 PM
Subject: Re: LF: RE: DLF passive received with earth antenna


Ehm, 18000m^2? I have just calculated 5000m^2. It is A = 1m^2 * 10EXP((-94--20)/20), right?

73, Stefan




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