Return to KLUBNL.PL main page

rsgb_lf_group
[Top] [All Lists]
<prev [Date] next>
[Advanced]
 <prev [Thread] next>

Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated

from [Stefan Schäfer] [Permanent Link][Original]
To: [email protected]
Subject: Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated
From: Stefan Schäfer <[email protected]>
Date: Thu, 09 Sep 2010 11:04:05 +0200
In-reply-to: <7304C3CD17394F5B81C72D1A36628D0A@IBM7FFA209F07C>
References: <[email protected]> <[email protected]> <[email protected]> <[email protected]> <[email protected]> <[email protected]> <7304C3CD17394F5B81C72D1A36628D0A@IBM7FFA209F07C>
Reply-to: [email protected]
Sender: [email protected]
User-agent: Mozilla/5.0 (Windows; U; Windows NT 6.1; de; rv:1.9.1.8) Gecko/20100227 Thunderbird/3.0.3
Hi Chris,

Yes, right. But my _expression_ is the same. 0,707 = 1/sqrt(2), so U^2/R = P =(û/sqrt(2))^2/R =û^2/2/R =û^2/2*R. Measuring 100 Vp at 50 Ohm is 100 W :-)

73, Stefan


Am 09.09.2010 10:11, schrieb Chris:
Hi Stefan,
I thought the power was the RMS voltage squared (i.e. peak voltage X 0.707) divided by the resistance.
Chris, G4AYT.
----- Original Message -----
Sent: Tuesday, September 07, 2010 9:31 PM
Subject: Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated

Roger,

For measuring the output power take a 50 Ohm dummy load (50, not 55 Ohms or so) and measure the peak voltage with an oscilloscope. Type this into the excel file and calculate the output power (P=(û)^2/(2*R)).

73, Stefan



[More with this subject...]
<Prev in Thread] Current Thread [Next in Thread>
Previous by Date:  LF: Calculation, Chris
Next by Date:  LF: RE: Off topic, Rik Strobbe
Previous by Thread:  Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated, John Rabson
Next by Thread:  Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated, Stefan Schäfer
Indexes:  [Date] [Thread] [Top] [All Lists]