Return to KLUBNL.PL main page

rsgb_lf_group
[Top] [All Lists]

LF: RE: Filter expert needed - Mystery of the lost real zero.

To: <[email protected]>
Subject: LF: RE: Filter expert needed - Mystery of the lost real zero.
From: "Mike Underhill" <[email protected]>
Date: Fri, 27 Apr 2007 14:33:10 +0100
Delivered-to: [email protected]
Importance: Normal
In-reply-to: <[email protected]>
Reply-to: [email protected]
Sender: [email protected]
Thread-index: AceIwLJP6Bu/ihvVQlSQVCcNLuIYyQADHhlA

Andy

 

For a second zero on the HF side try an inductor across the ‘zero’ capacitor.  The trouble is that it will have to have the same reactance as this 1.5p capacitor and that may not be easily realisable in practice.  The inductor could also go between resonators 1 and 3 or 3 and 5 I think.  If the inductor value is too high you can use a small ‘link’ coil on each of the resonators to be inductively coupled and connect these by a pair of twisted wires.  Getting the coupling right can be fiddly. You can get another LF zero rather than the wanted HF zero, I think, if you get the phasing wrong. 

 

I hope this helps but it is some time since I taught this stuff. Good luck.

 

Mike – G3LHZ

 

 

 


From: owner-
[email protected] [mailto:owner-[email protected]] On Behalf Of Andy Talbot
Sent:
27 April 2007 12:36
 Subject: LF: Filter expert needed - Mystery of the lost real zero.

 

Is there anyone monitoring these groups/reflector who knows the deep insides of filter design theory?

 

I've just synthesized a straightforward 50- 75MHz 5th order Top-C-coupled  bandpass filter to form part of a frequency converter that will feed an SDR-IQ digital receiver.   While playing with the filter design using a circuit analysis package, and recalling satellite microwave cavity filter designs from the dim-and-distant past, I remembered that by arranging cross-coupling between non adjacent resonators, it was possible to form pairs of real zeros in the upper and lower stop bands respectively.  These convert the filter to an elliptic type response, and considerably improve the cut-off.  I also recall it was a very critical thing to set up.  

 

So, I tried adding an additional cap between resonators 2 and 4, got a wonderful 10 - 20dB improvement in the low end cut-off response around 40MHz exactly where it was needed,  BUT ONLY THE ONE REAL-ZERO COULD BE FOUND !!!  There is absolutely no sign af any second null above the passband.

 

Where's it gone?  Shouldn't they always come in pairs?  This is really bugging me, I can't sleep at night, can anyone explain? 

Could it be because a top-coupled - C  BPF is non-symmetrical?

 

Full circuit details can be found at    http://www.scrbg.org/g4jnt/50-75bpf.pdf

 

Andy  G4JNT


No virus found in this outgoing message.
Checked by AVG Free Edition.
Version: 7.5.463 / Virus Database: 269.6.1/777 - Release Date: 26/04/2007 15:23

<Prev in Thread] Current Thread [Next in Thread>