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Re: LF: Untuned loops

from [Andy] [Permanent Link][Original]
To: [email protected]
Subject: Re: LF: Untuned loops
From: "Andy" <[email protected]>
Date: Tue, 15 Mar 2005 12:30:40 -0000
Reply-to: [email protected]
Sender: [email protected]
Thanks to all respondees - I knew it was a simple formula and was (theroretically) an exact way of determining field strength.  Just need to make sure the input impedance of the voltmeter is significantly higher than the loop impedance to avoid any loading effects.
 
(Someone here wants to measure the field strength of a transmission in the HF band)
 
Andy   G4JNT
 
-----Original Message-----
From: [email protected] <[email protected]>
To: [email protected] <[email protected]>
Date: 2005/03/15 10:58
Subject: Re: LF: Untuned loops

 
Hi Andy
 
 U = omega * µo * H * area 
 
with µo = 4 * pi * 10^-7 Vs/A/m, omega = 2 * pi * f .

73 de Markus, DF6NM
 
-----Original Message-----
From: Andy <[email protected]>
To: [email protected]
Sent: Tue, 15 Mar 2005 09:01:51 -0000
Subject: LF: Untuned loops

Can anyone recall this equation, I know it was mentioned on this reflector before...
 
What is the output voltage for an untuned small loop into an arbitrarily high impedance?  It is proportional to H, and presumably F^2, and I seem to recall it is an absolute value, virtually un-influenced by losses, conductor diameter etc.  Therefore can be used for accurate H field (and hence far field radiation) signal strength measurements.
 
Andy  G4JNT
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