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| To: | [email protected] |
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| Subject: | Re: LF: Untuned loops |
| From: | [email protected] |
| Date: | Tue, 15 Mar 2005 04:56:01 -0500 |
| In-reply-to: | <000d01c5293d$a1ddf8f0$0e8cf8d4@standalone> |
| References: | <000d01c5293d$a1ddf8f0$0e8cf8d4@standalone> |
| Reply-to: | [email protected] |
| Sender: | [email protected] |
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Hi Andy
U = omega * µo * H * area
with µo = 4 * pi * 10^-7 Vs/A/m, omega = 2 * pi * f .
73 de Markus, DF6NM -----Original Message-----
From: Andy <[email protected]> To: [email protected] Sent: Tue, 15 Mar 2005 09:01:51 -0000 Subject: LF: Untuned loops Can anyone recall this equation, I know it was mentioned on this reflector before...
What is the output voltage for an untuned small loop into an arbitrarily high impedance? It is proportional to H, and presumably F^2, and I seem to recall it is an absolute value, virtually un-influenced by losses, conductor diameter etc. Therefore can be used for accurate H field (and hence far field radiation) signal strength measurements.
Andy G4JNT |
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