Re: LF: Lost current in a coil

[riese-k3djc@juno.com]

 

Exactly

 

if the current were the same than you would have a perpetual

motion machine where more power is coming out than is going in.

the coil is ,, in the simple case,, acting as a transformer matching the 50 Ohm

to the higher impedance of the aerial

 

we needn't disobey the law of ,,, conservation

 

be nice if we could,, though

 

Bob K3DJC

 

 

As an example let the inductance of the coil  be 5mH. Then its reactance at 136kHz is 4270 ohm.
With an aerial current of for instance 2A flowing through the coil the voltage at the top of the coil will be
2 * 4270 = 8541V higher than at the bottom. 
So total voltage at the top will be 70 + 8541 = 8610V.

73, Dick, PA0SE