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RE: LF: Ground loss

To: [email protected]
Subject: RE: LF: Ground loss
From: "john sexton" <[email protected]>
Date: Tue, 14 May 2002 05:47:31 -0400 (EDT)
Reply-to: [email protected]
Sender: <[email protected]>
Hi Sasha,
Are you sure that you have written the formula correctly?

Omega (2 Pi f) appears in "a" in the numerator and in "Xc" in the denominator and therefore cancels out, making the formula frequency independent!

Perhaps there is a typo??

73, John, G4CNN


--- On Tue 05/14, Alexander S. Yurkov wrote:
>
> Hi LF Group
>
> > On Sat, 23 Mar 2002, john sexton wrote:
> > If you do find a model that works, please let us know.
>
>
> On the base of my own "generalased mirror reflection theory" I
> just have
> derive the formula for ground loss resistance:
>
>
> R = (lant/lcp)*a*Xc
>
> where:
>
> lant - wire length of antenna,
> lcp - wire length of ground system (conterpoint),
> a = (eps0*w)/s,
> eps0 - dielectric constant (8.85e-12 F/m),
> w = 6.28*f - circular frequency,
> s - ground conductivity.
> Xc = 1/(w*C) - antenna reactance,
> C - antenna capasitance.
>
> For 136 kHz and s=1 mSm/m a is about 0.01
>
>
> The formula is very aproximative but yelds reasonable value of R.
>
> Now I work on more advanced formula wich should be more accurate.
>
> Any coments please!
>
> 73 de RA9MB/Alex
> http://www.qsl.net/ra9mb
>
>
>
>


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