To: | <[email protected]> |
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Subject: | LF: Re: + 7dB in 424uHz , convert to 2.5Khz ? |
From: | "James Moritz" <[email protected]> |
Date: | Sun, 11 Mar 2012 13:17:17 -0000 |
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Dear Graham, LF Group, How do you scale these uHz d/b levels to other bandwidth's ? If the b/w is 848 uHz is the dB level + 3.5 dB ? + 7dB in 424uHz , convert to 2.5Khz b/w? The noise power is proportional to the bandwidth; the signal power stays the same. So the SNR is inversely proportional to the bandwidth. It can be calculated like this: 2.5kHz / 424uHz = 5.9 x 10^6 10 log10 (5.9 x 10^6) = 67.7dB SNR in 2.5kHz BW = (SNR in 424uHz BW) - 67.7dB = 7dB - 67.7dB = -60.7dB Cheers, Jim Moritz 73 de M0BMU |
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