Graham.
With that small antenna you might be lucky if it is 0.1% efficient,
therefore to get 1w erp you need 1Kw less 2.6db ie 555 watts to the
antenna
feed point.
If you are using a linear pa at 50% eff you would need a DC input of 1.110
Kwatts or a class D at 70% eff 793 watts.
This is a rough estimate, other factors need consideration as explained
before.
You probably know all about the subject anyway.
To measure the far field properly an airborne platform is necessary to get
a
clear run and avoid obstructions like buildings and trees etc. This is the
procedure used professionally. If you have a friend in the RAF this might
help
mal/g3kev
____________________________________________________________
I was typing 'fields' into google and can across this , nicely framed by
the boys
from Liverpool
http://uk.youtube.com/watch?v=Ywg-PdeGVL0
'A friend in the RAF' , Guess that's a new take on 'Aerial' measurements,
http://uk.youtube.com/watch?v=rJX03LcmNpU
1.1 Kw dc input may be be 'pushing' things a little too far hihi
G ..
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