To: | [email protected] |
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Subject: | Re: LF: CLASS D E |
From: | "Andy Talbot" <[email protected]> |
Date: | Mon, 5 Nov 2007 12:26:01 +0000 |
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Its not difficult to measure RF voltage at this frequency. A scope calibration at DC will extrapolate accurately. Then you can measure I using a current transformer / resistor. Getting within a few percent shouldn't tax any abilities provided you can calibrate a scope at DC. The mistake I made the time I "saw" 105% efficiency was, I seem to recall, due to forgetting the 4/pi factor when filtering the fundamental component out of a square wave - all old history now. Efficiency in class D/E amplifiers falls when the match is not purely resistive, and the devices are forced to switch at other than the zero crossing point of the current waveform. Andy G4JNT www.scrbg.org/g4jnt On 05/11/2007, hamilton mal <[email protected]> wrote: > Hi all > Tnx to all for the information, but some of the figures do not work out. How > are the % figures measured. > One simple method is to calculate the DC input PWR in watts (I x V) then > using an RF current meter calculate the PWR out (Isq x R) let R be the norm > 50 ohm D/load. Compare the two figures and calculate the Eff % > 73 de Mal/G3KEV > > > > |
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