Jim,
I think there is a Lowfer-like solutin to this problem. Seems to me that if
everything is assumed to be 'ideal' or 'loss-free' including the wires,
there would still have to be a TX loop antenna formed by the connections. At
the instant of connection there would be radiation of 25uJ at a frequency
dependent on the capacitance and inductance of the components.
(See, there is no problem anyone can introduce that has no oportunity for me
to put in a plug for TX loop antennas! <G>)
Have a good, mind relaxing, weekend!
Bill A
This simple puzzle caused more discussion in my office this morning than it
had any right to....
Here is another conundrum along similar lines - you have two identical,
loss-free 1uF capacitors, one is charged to 10V, the other is discharged.
You then connect the two in parallel so the total C is now 2uF - charge
will flow from the charged capacitor into the discharged capacitor.
Assuming charge Q is conserved, and that Q=CV, the voltage must now be 5V.
But the stored energy in a capacitor =1/2CV^2, so with the single charged
capacitor, the stored energy is 1/2 x 1u x 100 = 50uJ, while with both
capacitors in parallel it is only 1/2 x 2u x 25 = 25uJ. So where has the
other 25uJ gone?
Cheers, Jim Moritz
73 de M0BMU
_____________________________________________________________________
This e-mail has been scanned for viruses by the WorldCom Internet Managed
Scanning Service - powered by MessageLabs. For further information visit
http://www.worldcom.com
_____________________________________________________________________
This e-mail has been scanned for viruses by the WorldCom Internet Managed
Scanning Service - powered by MessageLabs. For further information visit
http://www.worldcom.com
|
