G'day Wolf,
I have been trying to understand the information you gave as below:-
Using these settings to receive:
Sample rate = 11025 Hz
FFT type = complex, center frequency = 650 Hz (preferred "AF IF")
FFT decimation = 128
FFT input size = 16384
FFT resolution = 5.3 milliHertz
Waterfall scroll rate = 30 seconds
I am interested to learn how you get the 5.3mHz resolution. From my
understanding the resolution of an FFT of 16384 samples at sample rate
11025Hz would be - 11025/16384 = 0.673Hz. By decimating in time 128
records (and averaging) I thought there is no gain in resolution, but you
get an increase in S/N of sqrt(128) in each of these 0.673Hz bins. How
are the 5.3mHz bins generated ?
73s Steve Olney (VK2ZTO/AXSO - QF56IK : Lat -33 34 07, Long +150 44 40)
=============================================
HomePage URL: http://www.zeta.org.au/~ollaneg
Containing:-
ULF, ELF, VLF & LF Experimentation
MF 22m Experimentation
InfraSonic Experimentation
Laser Comms DX
=============================================
| 