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LF: Re: Low loss inductors

To: [email protected]
Subject: LF: Re: Low loss inductors
From: "john sexton" <[email protected]>
Date: Wed, 1 Mar 2000 10:06:33 -0800 (PST)
Reply-to: [email protected]
Sender: <[email protected]>
On Sat, 26 Feb 2000 14:00:10 GMT
"Andy Talbot" wrote:

For an estimate of losses :
Skin depth of copper at 137kHz is approximately 0.18mm      From    D = 503

SQRT(Resistivity / Freq / uo) For Cu Resistivity = 1.7E-8 Ohms / m, and uo (magnetic permeability) =
1
Diameter of centre conductor = 2.5mm (near enough anyway) so cross sectional area of conducting path is 0.18mm * 2.5mm = 0.45E-6 m^2 RF Resist = Resisivity * Length / Area = 1.7E-8 * 370m / 0.45E-6m^2 = 14 ohms.
For a quick estimate assume the braid losses are a lot less than the centre

conductor as they have a much larger surface area, so can be ignored (that may not necessaily be the case) and we can also ignore
dielectric losses (a reasonable assumption at these freqs) so Q = Xl / R
= 1722 / 14 = 123 Which is about what I got on my 5mH conventional coil of 1.5mm wire,
300mm
diameter and 400mm long.

You forgot a Pi in the calculation of the cross sectional area. The
circumference is Pi D, not just D. Therefore cross sectional area is approx.
1.41E-6 m^2
and RF Resist = 1.7E-8 * 370m / 1.41E-6m^2 = 4.46 ohms.
So Q = 1722/4.46 = 386, which is somewhat better than your conventional
coil.

John, G4CNN






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