To All from PA0SE: Jim, M0BMU wrote: The un-neat thing about an oil dielectric is its propensity for catching fire... also, I don't think it has particularly low loss at RF - although a lot of big TX
Hi Jim While I have similar reservations there have been a few oil filled tuning caps used successfully here with tesla coils-not the best parallel to use but certainly close enough to make the prosp
Dear Dave, LF Group, At 08:43 09/11/2002 +1300, you wrote: The neat thing with the oil dielectric is it is basically self healing , even if it does arc over- no permanent capacitor damage will result
Both these problems are standard fare in 'older' physics texts- anyone rember Resnick & Halliday, for example? There is another more interesting side to Andy's problem as stated however. Consider the
Jim, I think there is a Lowfer-like solutin to this problem. Seems to me that if everything is assumed to be 'ideal' or 'loss-free' including the wires, there would still have to be a TX loop antenna
Dear Andy, LF Group, At 14:57 08/11/2002 +0000, you wrote: Can tell you come from a university background Jim, do you ask that of applicants for courses at herts.ac? I was asked exactly the same ques
Hi Andy, Jim and all, This is a great question, because it tells a lot about the background of the person answering, even if the answer is "correct". The engineer will say that most of the "missing"
Can tell you come from a university background Jim, do you ask that of applicants for courses at herts.ac? I was asked exactly the same question when applying for Southampton Uni. in 1976. Andy G4JNT
When C decreases from 10 uF to 1 uF voltage increases from 10 V to 100 V So energy E=C*U^2/2 changes from 1e-5*10*10/2=0.5e-3 J to 1e-6*100*100/2= 0.5e-2 J. Where did extra energy come from? To drain
Here is another conundrum along similar lines - you have two identical, loss-free 1uF capacitors, one is charged to 10V, the other is discharged. You then connect the two in parallel so the total C i
ha ha Yes, you said 25µJ per capacitor..... 73 Jan-Martin, LA8AK --Opprinnelig melding-- Fra: James Moritz [mailto:[email protected]] Sendt: 8. november 2002 12:52 Til: rsgb_lf_group@blacksheep.
Dear Andy, LF group, Here is another conundrum along similar lines - you have two identical, loss-free 1uF capacitors, one is charged to 10V, the other is discharged. You then connect the two in para
Hi, Andrew and Group. An oil filled capacitor consists of two plates separated by a dielectric made of oil with a dielectric constant of 10. The capacitance is 10uF and it is charged to 10V. The oil
This simple puzzle caused more discussion in my office this morning than it had any right to. Have a ponder while waiting for next QRSS symbol to come through. Andy G4JNT -- From Circuit Cellar magaz
