Hello Andy, I had the same thought, mean power or peak power ? I did choose for peak power as this is the "real world" limitation for high efficiency class D or class E amplifiers. At +80% efficiency
You don't need a linear PA for WSPR. It is constant amplitude MFSK. Timing only has to be within a few seconds, and an internet time server can do that You will need an upconverter though - which I a
Hello Rik / LF Those results tie in well with my tests on 500kHz. Having run WSPR spaced with QRS3 for some years I was surprised how easy it was to read QRS3 FANT0M tagged to OP4 compared with the O
...of course - thinking this through further... QRSS is also about 50% duty cycle, so if we insist on the mean power rule for Opera, it has to apply to QRSS as well. So leave the QRSS and Op curves w
Dear all, the results of the "QRSS3 challenge" can be found at http://on7yd.strobbe.eu/QRSS/ Hit refresh if you still see the old challenge. Thanks to all who participated ! 73, Rik ON7YD - OR7T Van:
Hi RIk - one comment / question I have ... When you generasted the Opera and WSPR audio files, did you take into account that Opera should be compared using the mean power? With its 50% duty cycle, t
account that Opera should be compared using the mean power? With its 50% duty cycle, this means an Opera Tx has to have twice the power rating of one running WSPR for equal S/N ratios...> ... But on
Thanks Andy. Yes, that is what I meant! 73s Roger On 8 February 2012 20:24, Andy Talbot <[email protected]> wrote: You don't need a linear PA for WSPR. It is constant amplitude MFSK. Timing only h
Dear Andy, Rik, LF Group, account that Opera should be compared using the mean power? With its 50% duty cycle, this means an Opera Tx has to have twice the power rating of one running WSPR for equal
Communications theory doesn't care if your transmitter can deliver more power. It only takes into account the actual power is does transmit If you are limited by PA power output capability, then at O
