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RE: LF: Radiated power at PA0SE

To: [email protected]
Subject: RE: LF: Radiated power at PA0SE
From: "Andrew Talbot" <[email protected]>
Date: 14 Aug 2001 16:11:22 +0100
Reply-to: [email protected]
Sender: <[email protected]>
......................
 I found a FS of 370 microvolt/metre. From this follows an impressive
radiated
power (EIRP) of 52 milliwatt. I guess). what program did you use ?

You don't need a programme, just work from basic theory ......

From Ohms law  E^2 / Zo  (of free space = 377 ohms)   =   Watts / m^2
At a distance R from an omnidirectional radiator (the definition of EIRP),
all the transmitted power is spread out over a sphere of surface area 4 * PI * R^2, which is equal to your measured power density in W/m^2
So EIRP of Tx   =    (Watts / m^2) * 4.PI.R^2   =  E^2 / 4 * PI * R^2
where E isthe  measured field strength in Volts / metre
Then if you really want it in terms of dipole ERP, just subtract the magic
figure of 2.14dB ( or divide by 1.64) , ie. the gain of a dipole.

Andy  G4JNT


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