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LF: RE: R: Formula

To: [email protected]
Subject: LF: RE: R: Formula
From: "Talbot Andrew" <[email protected]>
Date: Wed, 7 Jun 2000 12:54:34 +0100
Reply-to: [email protected]
Sender: <[email protected]>
Ah -
I'd taken the factor of 30 outside the square root then.  Careless !!

Andy  'JNT

----------
From:   cesare tagliabue[SMTP:[email protected]]
Reply To:       [email protected]
Sent:   2000-06-07 12:11
To:     [email protected]
Subject:        LF: R: Formula

            Hi Walter
        The formula is derived from the general one that is: E =
SQR(30*P*G)/D. Being the gain G of an half-wave dipole equal to 1.64,
30*1.64 = 49.2, rounded to integer and written out of the square root
it
becomes 7. E is the field strength in V/mt, provided that P is in
Watts and
D in meter; in fact the field strength is independent from frequency.
        73  Cesare

Cesare Tagliabue   I 5 TGC
e-mail: [email protected]
url: http://www.dadacasa.com/i5tgc

-----Messaggio originale-----
Da: Walter Blanchard <[email protected]>
A: [email protected] <[email protected]>
Data: mercoledì 7 giugno 2000 11.58
Oggetto: LF: Formula


>I found the following in an article recently.
>
>Quote:
>
>"The intensity E (known as the field strength) of a transmission
>at a distance D from a source transmitting P watts of RF power via
>a half-wave dipole in a free, unobstructed space, can be estimated
>using the formula:
>
>E=(7*sqrt (P))/D.
>
>Thus, for a 2 watt transmitter, the theoretical field strength in
free
>space at one metre distance is approximately 10 V/m and at 100 metres
>distance 0.1 V/m"
>
>This formula is new to me and I can't find it in any
>textbooks I have.  Since it ignores frequency shouldn't
>it be power flux per unit area and not field strength?
>Can anyone tell me where it comes from?
>
>Walter G3JKV.
>
>
>
>




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