Very good point... of course it can't... - just saw the option in the design S/W and didn't actually try it out. OOPs !!!!!!! I've done this quite often with bandpass filters, where it does work
If its a passive L/C filter, why not do a version with unequal Zin and Zout and take advantage of the voltage gain in going from 50ohms to, say, 500 ohms? That will give you an apparant 10dB withou
Dear Andy, LF Group, ...Which all seems totally and utterly pointless. Might just as well slug one of the unequal impedances with an auxilliary R to make them equal, then design an equally terminated
Apparently one advantage of doubly terminated filters is that they are less sensitive to component tolerances than an equivalent singly-terminated filter - but in many cases the practical difference
Thank you all LFs. Thank you for all the info that you sent me, it looks they can be anything from 4k ohms upwards, this is ok for me, I am doing a Low Pass Filter to use with Winrad, F1, 20kHz, F2,
Hello Andy. I must admit I had not thought of that, so used to using equal impedances, I did use AADE for this and the component values came almost as standard values, I used the tolerance option of
Dear Andy, LF Group, Unfortunately, this doesn't quite work... If you think about it, at very low frequencies, any low-pass filter will just be a "straight through" connection, so in your example wil
Have just being playing with AADE, to try to see why it pretends to be able to do low pass filters with unequal impedances. All it appears to do is choose a set of values that maintains the specifi
