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1. LF: RE: loop inductance (score: 1): Author: "Ashlock,William" <[email protected]>; Date: Sat, 30 Mar 2002 13:28:10 -0500; Hi Alex, Here goes: L(uh) = .008s((ln(1.414s/2d)+.38) Where s = the length of a side in cm; d = diameter of conductor in cm; ln = natural logarithm This is for a single turn square loop. With the fin; /rsgb_lf_group-archives/html/rsgb_lf_group/2002-03/msg00014.html (10,252 bytes)

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