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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*LF\:\s+RE\:\s+VLF\s+\-\s+vertical\s+probe\s+measurements\s*$/: 4 ]

Total 4 documents matching your query.

1. Re: LF: RE: VLF - vertical probe measurements (score: 1)
Author: Chris Osborn <[email protected]>
Date: Fri, 15 Apr 2011 14:22:12 +0100 (BST)
Hello Stefan / Rik, Thanks for the response. I adjust the PA current by varying the drive level to the FET's so the PA supply voltage stays constant. I should have made that clear. 73 Chris G3XIZ --
/rsgb_lf_group-archives/html/rsgb_lf_group/2011-04/msg00215.html (12,795 bytes)

2. LF: Re: VLF - vertical probe measurements (score: 1)
Author: "James Moritz" <[email protected]>
Date: Fri, 15 Apr 2011 14:18:50 +0100
Dear Chris, LF Group, Assuming the antenna impedance seen by the TX stays the same (i.e. you are not changing output power by altering the antenna matching), the DC current drawn by the amplifier wil
/rsgb_lf_group-archives/html/rsgb_lf_group/2011-04/msg00456.html (12,397 bytes)

3. RE: LF: RE: VLF - vertical probe measurements (score: 1)
Author: Rik Strobbe <[email protected]>
Date: Fri, 15 Apr 2011 15:38:39 +0200
Chris, Since you alter the drive level I do assume the PA is linear. At lower input (and thus output) power the efficiency will drop, due to the bias current (ultimately at zero input level the effic
/rsgb_lf_group-archives/html/rsgb_lf_group/2011-04/msg00551.html (14,334 bytes)

4. LF: RE: VLF - vertical probe measurements (score: 1)
Author: Rik Strobbe <[email protected]>
Date: Fri, 15 Apr 2011 15:11:39 +0200
Hello Chris, maybe a stupid question (wouldn't be my first one): how do you alter the PA current ? If you change the PA current by changing the PA voltage then the output power will change more or le
/rsgb_lf_group-archives/html/rsgb_lf_group/2011-04/msg00675.html (11,826 bytes)


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