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Total 5 documents matching your query.

1. LF: RE: Re: a lot of ferrite (score: 1): Author: "Clemens Paul" <[email protected]>; Date: Sat, 12 Jan 2019 15:17:45 +0100; Hi Dimitris, I've made a calculation based on your data with the mini ring-core calculator and it says ľ = 1070 and AL = 937.5nH /N^2 So your first calculation seems to be right. 73 Clemens DL4RAJ; /rsgb_lf_group-archives/html/rsgb_lf_group/2019-01/msg00102.html (10,736 bytes)
2. Re: LF: RE: Re: a lot of ferrite (score: 1): Author: Dimitrios Tsifakis <[email protected]>; Date: Sun, 13 Jan 2019 06:55:10 +1100; Hi Clemens, the mistake I made the first time was that I incorrectly set the ID/OD difference of the equivalent ring to be 2 cm instead of 4... 73, Dimitris VK2COW; /rsgb_lf_group-archives/html/rsgb_lf_group/2019-01/msg00117.html (13,298 bytes)
3. RE: LF: RE: Re: a lot of ferrite (score: 1): Author: "Clemens Paul" <[email protected]>; Date: Sat, 12 Jan 2019 21:23:07 +0100; Hi Dimitris, The cross section of the rods or equivalent toroid is 2cm x 10cm. If you take 10cm as height the ring is 2cm thick. Hence the OD/ID difference is indeed 2cm not 4cm... 73 Clemens DL4RAJ; /rsgb_lf_group-archives/html/rsgb_lf_group/2019-01/msg00122.html (13,968 bytes)
4. Re: LF: RE: Re: a lot of ferrite (score: 1): Author: Dimitrios Tsifakis <[email protected]>; Date: Sun, 13 Jan 2019 08:01:52 +1100; Hi Clemens, A difference of 2 cm would be true for the radius but not for the diameter. I would define the inner and outer diameter as seen in this picture: https://cdn.app.compendium.com/uploads/use; /rsgb_lf_group-archives/html/rsgb_lf_group/2019-01/msg00129.html (11,532 bytes)
5. RE: LF: RE: Re: a lot of ferrite (score: 1): Author: "Clemens Paul" <[email protected]>; Date: Sat, 12 Jan 2019 22:27:13 +0100; No,you are right. :-) Thanks! 73 Clemens DL4RAJ a4a68a1f850a9ab6f4627c1d493fd1/hose_sizing_parker_hose_products_divi>sion_tube_diameter_300px.jpg; /rsgb_lf_group-archives/html/rsgb_lf_group/2019-01/msg00135.html (11,729 bytes)

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