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References: [ +subject:/^(?:^\s*(re|sv|fwd|fw)[\[\]\d]*[:>-]+\s*)*LF\:\s+RE\:\s+An\s+answer\s+to\s+Monday\'s\s+puzzle\s*$/: 4 ]

Total 4 documents matching your query.

1. LF: RE: An answer to Monday's puzzle (score: 1)
Author: "Alberto di Bene" <[email protected]>
Date: Mon, 11 Nov 2002 18:32:13 +0100
[...] Congrats Hugh, you worked it out - use a thermometer, and to be really scientific measure the temperature when shorted, and when open circuit. Or, maybe simpler, use a compass near the black b
/rsgb_lf_group-archives/html/rsgb_lf_group/2002-11/msg00245.html (8,719 bytes)

2. Re: LF: RE: An answer to Monday's puzzle (score: 1)
Author: "Steve Thompson" <[email protected]>
Date: Mon, 11 Nov 2002 15:59:38 +0000
Steve
/rsgb_lf_group-archives/html/rsgb_lf_group/2002-11/msg00246.html (8,558 bytes)

3. LF: RE: An answer to Monday's puzzle (score: 1)
Author: "Andy talbot" <[email protected]>
Date: Mon, 11 Nov 2002 14:17:03 +0100
No Steve, this doesn't work. - Although I fell into that trap initially. For a Thevenin network, if you connect an external 1V source, you will get either 2A or zero flowing depending on polarity, as
/rsgb_lf_group-archives/html/rsgb_lf_group/2002-11/msg00248.html (10,821 bytes)

4. LF: Re: An answer to Monday's puzzle (score: 1)
Author: "g6tmk" <[email protected]>
Date: Mon, 11 Nov 2002 12:59:02 +0100
I thought the whole point of these theoretical sources is they were interchangeable. I did wonder if you could use a thermometer to measure the temperature rise, as the 1 ohm resistor would dissipate
/rsgb_lf_group-archives/html/rsgb_lf_group/2002-11/msg00250.html (9,862 bytes)


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