To: | [email protected] |
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Subject: | Re: LF: Re: HB9ASB... |
From: | "Roelof Bakker" <[email protected]> |
Date: | Thu, 11 Aug 2011 12:26:27 +0200 |
In-reply-to: | <CAA8k23SzJFi2tGfkN0fSRMi9bCwa_63uWiAZSV3P+dxcKfuSpg@mail.gmail.com> |
References: | <[email protected]> <67A6F7BF45BF4A0193A3DCB53000A283@PcMinto> <008401cc56ce$2f1fb2c0$0401a8c0@xphd97xgq27nyf> <12C475F3F4C84B818461753F2E8A60A6@PcMinto> <[email protected]> <8D68749D37B94275855FDBA46A3F6C97@PcMinto> <[email protected]> <CAA8k23SzJFi2tGfkN0fSRMi9bCwa_63uWiAZSV3P+dxcKfuSpg@mail.gmail.com> |
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Hello Andy, The antenna will work with an optical feedline. I can't imagine that fiber optic forms the other half of the dipole. The probe capacitance is rather low, about 3 pF.My guess is that the "counterpoise" is formed by the PCB part, carrying the buffer amplifier. The layout of the PCB art work has some effect on the received signal strength. Using leaded components, the pick up area measures 30 x 40 mm.A PCB with SMD parts will give the same output with an "antenna" measuring 24 x 30 mm. 73, Roelof, pa0rdt |
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