There fine
here.
Mike>WE0H
http://www.we0h.us/lf.html
-----Original
Message-----
From:
[email protected] [mailto:[email protected]]On Behalf Of John W Gould
Sent: Tuesday, November 12, 2002
1:02 PM
To: [email protected]
Subject: LF: Puzzles
Fine! I personally
don't mind as I find them interesting - the question is do the majority of the
reflector users mind the scope of the reflector to broaden to include such
technical intrigues? I must admit that it is better than spam and helps
to keep the brain going between M-Class flares and other discussions more
relevant to LF.... I'm happy to change the unwritten scope for the
reflector if we don't otherwise have any serious dissenters, so (brief)
comments please either way ...
73 John, G3WKL
-----Original
Message-----
From:
[email protected] [mailto:[email protected]]On Behalf Of Andy talbot
Sent: Tuesday, November 12, 2002
18:34
To: [email protected]
Cc: ME Work
Subject: LF: Re: Tuesday's riddle
Right,
done it. Now that's very interesting !!!!!!
Exactly
as you specified, even down to the same 2N2222 device. The B-E junction
breaks down at 7.56V, ie. Vbe = (minus) -7.56V With a DVM,
10M input resistance, Vcb = (plus) +0.35V almost as if it is acting
as a voltage inverter, no wonder you ripped the can apart. That shouldn't
be, BUT...
The
tunnelling (or whatever the current carriers do in a zener) are probably
wizzing across the B-E junction and hitting the C-B junction, then
overshooting and slowing down or something, so generating a voltage. Just
inspired guessing. Any solid state physicists out there
?....
How can
anyone want puzles like this removed from the reflector John ?
Andy
G4JNT
-----
Original Message -----
To: [email protected]
Sent: Monday, November 11,
2002 7:58 PM
Subject: LF:
Tuesday's riddle
Hi group,
this little experiment was pointed out to me by Ralph, DL2NDO a few years ago:
You need an ordinary NPN transistor (eg. 2N2222), a 9V battery, a 1k resistor
and a voltmeter. Connect the negative battery terminal to the base and the
positive to the emitter, via the resistor. Now predict the voltage drop between
collector and base. Can't be too hard...
Then measure it - you'll be surprised. Any explanations? We finally ended up
opening the poor transistor's case.
Have fun
Markus, DF6NM
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