Dear all

Contemplating making one of Peter's 'Superloop' antennas and find that I
have aprox. 100 metres of Crawley Litz in stock. Now Peter's article sez
I have to cut 11 x 16.3m lengths of wire = 180 metres of wire, so I

But before I go rushing off to Derek to buy some more, a simple sum
casts some doubt on Peter's calculations. His loop has 2 metre sides and
it has 4 sides so one turn equals 8 metres, not 16m, in which case I
have enough Litz!

Am I missing something, or should I go back to school for a refresher
course in sums?

73, Tom G3OLB