To: | LineOne <[email protected]> |
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Subject: | Re: LF: How can you tell if a Class D amp output transformer is starting to saturate? |
From: | Andy Talbot <[email protected]> |
Date: | Thu, 3 May 2018 17:05:43 +0100 |
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The peak of the fundamental sine component in a square wave is 4/pi times the square wave amplitude (yes, it is bigger). The RMS of the sine is Peak / SQRT(2) . Take the two together and the RMS of your sine is therefore 0.9 * Peak of the square wave
So if you had a Vdd of 50V you would have 45V rms across each half of the winding, or 90V rms across the two halves. Which answers your other question Actually, thinking about what I've just said, you are putting the square wave though the transformer, not a sine. So in that case you have a bit more leeway in that it can go to the same peak value as the sine would have given you. Unless I'm building SMPSUs, I don't put square waves though transformers in transmitters - teh RF is always filtered beforehand. There is an equivalent equation for square waves and used in SMPSU design, it is V.t = N.A.B Now V is input voltage, t is the on-time , and N.A.B as before And yes, your area is correct. 1.58cm^2 = 0.000158m^2 Andy On 3 May 2018 at 16:36, N1BUG <[email protected]> wrote: I am still not sure whether I am using that equation correctly. |
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