To: | [email protected] |
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Subject: | Re: Fwd: Re: LF: VK1OD's analysis of the MiniWhip antenna |
From: | pat <[email protected]> |
Date: | Wed, 10 Jul 2013 19:53:38 +0100 |
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Of course, it also holds to be true that the "rest of the universe" that
is the "other plate" of my capacitor is also the "other plate" of
everyone else's similar capacitor and is the common circuit element to
which we are all referenced!
73 On 10/07/13 18:30, Pieter-Tjerk de Boer wrote: On Wed, Jul 10, 2013 at 05:58:44PM +1000, edgar wrote:Surely every conductor in the unit will have a difference in potential due to being in a electromagnetic field. Even in the legs of the FET. Although the potential will be extremely small.Yes, of course that's correct. I should have written that with a fiber optic cable instead of the coaxial cable, all circuit elements are coupled to the field at _almost_ the same place, and thus are at _almost_ the same potential, and thus _almost_ no signal will come out: very much less than with the coax still in place. B.t.w., some mini-whips are built using a metal can as the probe, with the entire electronics inside the can; such an arrangement would get quite close to zero output when the coax is replaced by the fiber optics. Anyway, it was originally claimed that the functioning of the mini-whip does not depend on the coaxial cable; I just intended to explain why I think it does. 73, Pieter-Tjerk, PA3FWM -- 73 de pat g4gvw es gd dx qth nr Felixstowe East Coast UK |
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