To: | [email protected] |
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Subject: | Re: LF: Re: Series loading coil |
From: | "Dick Rollema" <[email protected]> |
Date: | Sun, 01 Dec 2002 13:52:33 +0100 |
Reply-to: | [email protected] |
Sender: | <[email protected]> |
Sri I made a mistake in the equation for
L1; It should be L1 = L2 + L3 + 2k * square root L2 * L3 To M0WYE and All from PA0SE Hugh, M0WYE wrote: I've wound myself a coil on a bucket, the inductance is a bit low at the moment, the whole thing resonates no lower than 250kHz at present - so I've some work still to do before I transmit. I put lots of taps in, as suggested. This subject has been discussed on the reflector several times before. For coils to be used on the HF bands, for instance in the pi-network of a valved power amplifier or an aerial matching unit, it is usual to short circuit the unused part of the coil. If it is was left open the unused part, together with its distributed capacitance, could be come resonant on the working frequency and absorb a large part of the power. The short circuited part is only loosely coupled to the used part so there is only a small current flowing in it and this results in negligible power to be lost in the resistance of the short circuited turns. That the coupling is loose can be easily shown on paper. Using one of the formulas for the inductance of a single layer coil calculate: a. Inductance L1 of the total coil b. Inductance L2 of the used part of the coil c. Inductance L3 of the part to be short circuited. Now L1 = L2 + L3 + 2k * square root(L2 * L3). k is the coupling factor; k is between 0 and 1. You will find that k << 1. It is a different story for coils wound on a toroidal core of ferrite or powdered iron. k can then be almost one and the unused turns should NOT be short circuited, though this is often seen in designs for aerial tuners. For a loading/matching coil for the 136kHz band the chance of self-resonance in the unused part is remote. But when the unused turns are left open the voltage at the top end of the coil is higher that when they are short circuited. That is why I short circuit them. I found the aerial current being the same with the unused part open or short circuited. So the loss is negligible. 73, Dick, PA0SE ] ----- Original Message ----- |
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