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Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated

To: [email protected]
Subject: Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated
From: Stefan Schäfer <[email protected]>
Date: Thu, 09 Sep 2010 11:04:05 +0200
In-reply-to: <7304C3CD17394F5B81C72D1A36628D0A@IBM7FFA209F07C>
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Hi Chris,

Yes, right. But my _expression_ is the same. 0,707 = 1/sqrt(2), so U^2/R = P =(û/sqrt(2))^2/R =û^2/2/R =û^2/2*R. Measuring 100 Vp at 50 Ohm is 100 W :-)

73, Stefan


Am 09.09.2010 10:11, schrieb Chris:
Hi Stefan,
I thought the power was the RMS voltage squared (i.e. peak voltage X 0.707) divided by the resistance.
Chris, G4AYT.
----- Original Message -----
Sent: Tuesday, September 07, 2010 9:31 PM
Subject: Re: LF: 137.5kHz WSPR Tuesday evening - reports appreciated

Roger,

For measuring the output power take a 50 Ohm dummy load (50, not 55 Ohms or so) and measure the peak voltage with an oscilloscope. Type this into the excel file and calculate the output power (P=(û)^2/(2*R)).

73, Stefan



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