To: | <[email protected]> |
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Subject: | LF: Re: 500 khz ERP |
From: | "James Moritz" <[email protected]> |
Date: | Sat, 26 May 2007 11:25:21 +0100 |
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Dear Mal, LF Group, > To justify my ERP argument and keep the maths simple, look at examples > below. > > 1. 10W rf output to the antenna and an efficiency of the average antenna 1% > the ERP would be 0.1W erp... The maths is not quite as simple as this - to calculate ERP in this way, the directivity of the antenna compared to the reference 'half-wave dipole in free space' must also be included: ERP = (TX power) x (Antenna Efficiency) x (Directivity) Assuming the antenna is a vertical over a ground plane that is a small fraction of a wavelength long (or a small loop over a ground plane), its directivity can be assumed to be 2.6dB over a dipole, i.e. a factor of 1.8. So the ERP in your example would be 0.18W ERP. It is important to bear this in mind in correspondence with Ofcom! Cheers, Jim Moritz 73 de M0BMU |
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