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From: Andy Talbot <andy.g4jnt@gmail.com>
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Moving to 496.4Hz now ?

Frequency expressed in dB has to take the 10.LOG form, not 20.LOG

Consider P = kTB

'jnt



Thanks also from here to all participants (feline and human)! Next step -
> reduce frequency by 24.4334 dB?
>
> All the best,
> Markus (DF6NM)
>
>
>
>

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<div dir=3D"ltr">Moving to 496.4Hz now ?<div><br></div><div>Frequency expre=
ssed in dB has to take the 10.LOG form, not 20.LOG</div><div><br></div><div=
>Consider P =3D kTB =C2=A0</div><div><br></div><div>&#39;jnt</div><div><br>=
<div class=3D"gmail_extra"><br><div class=3D"gmail_quote"><br><blockquote c=
lass=3D"gmail_quote" style=3D"margin:0 0 0 .8ex;border-left:1px #ccc solid;=
padding-left:1ex">

<div>
<div style=3D"color:black;font-family:arial;font-size:10pt"><font color=3D"=
black" face=3D"arial">Thanks=C2=A0also from here to all participants (felin=
e and human)! </font>Next step=C2=A0- reduce frequency by 24.4334 dB?</div>

<div style=3D"color:black;font-family:arial;font-size:10pt">=C2=A0</div>
All the best,</div>

<div>Markus (DF6NM)</div>

<div><br>
=C2=A0</div>

<div><br></div></blockquote></div></div></div></div>

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