Return-Path: Received: from mtain-dc02.r1000.mx.aol.com (mtain-dc02.r1000.mx.aol.com [172.29.64.130]) by air-da04.mail.aol.com (v128.1) with ESMTP id MAILINDA041-85e64bafebc2348; Sun, 28 Mar 2010 19:52:34 -0400 Received: from post.thorcom.com (post.thorcom.com [193.82.116.20]) by mtain-dc02.r1000.mx.aol.com (Internet Inbound) with ESMTP id BF36F38000097; Sun, 28 Mar 2010 19:52:32 -0400 (EDT) Received: from majordom by post.thorcom.com with local (Exim 4.14) id 1Nw2G4-00009c-NN for rs_out_1@blacksheep.org; Mon, 29 Mar 2010 00:51:08 +0100 Received: from [193.82.116.32] (helo=relay1.thorcom.net) by post.thorcom.com with esmtp (Exim 4.14) id 1Nw2G4-00009T-4k for rsgb_lf_group@blacksheep.org; Mon, 29 Mar 2010 00:51:08 +0100 Received: from lnx503.hrz.tu-darmstadt.de ([130.83.156.232]) by relay1.thorcom.net with esmtp (Exim 4.63) (envelope-from ) id 1Nw2G1-0002ub-GN for rsgb_lf_group@blacksheep.org; Mon, 29 Mar 2010 00:51:08 +0100 Received: from FILE-SERVER-HST.hst.e-technik.tu-darmstadt.de (File-Server-HST.hst.e-technik.tu-darmstadt.de [130.83.212.129]) by lnx503.hrz.tu-darmstadt.de (8.14.2/8.14.2/HRZ/PMX) with SMTP id o2SNp2eJ023632 for ; Mon, 29 Mar 2010 01:51:02 +0200 (envelope-from schaefer@hst.tu-darmstadt.de) Received: from [127.0.0.1] (helo=File-Server-HST.hst.e-technik.tu-darmstadt.de) by FILE-SERVER-HST.hst.e-technik.tu-darmstadt.de with AVK MailGateway; for ; Mon, 29 Mar 2010 01:51:02 +0200 Content-class: urn:content-classes:message MIME-Version: 1.0 X-MimeOLE: Produced By Microsoft Exchange V6.5 Date: Mon, 29 Mar 2010 01:48:20 +0200 Message-ID: <38A51B74B884D74083D7950AD0DD85E82A1BB3@File-Server-HST.hst.e-technik.tu-darmstadt.de> X-MS-Has-Attach: X-MS-TNEF-Correlator: <38A51B74B884D74083D7950AD0DD85E82A1BB3@File-Server-HST.hst.e-technik.tu-darmstadt.de> Thread-Topic: LF: Question about ground impedance at 8.97 KHZ **UPDATE Thread-Index: AcrN8S1PY6fYjzFlR9OGAQAfA1r4FAAEbIJ9ACgenCAAC3LsMQ== References: From: =?iso-8859-1?Q?Stefan_Sch=E4fer?= To: X-AVK-Virus-Check: AVB 19.848;28.03.2010 X-PMX-TU: seen v0.99a by 5.5.9.388399, Antispam-Engine: 2.7.2.376379, Antispam-Data: 2010.3.28.233919 X-PMX-SPAMCHECK: outgoing mail X-Spam-Score: 0.0 (/) X-Spam-Report: autolearn=disabled,none Content-Type: multipart/mixed; boundary="----_=_NextPart_001_01CACED1.85AE55BD" Subject: AW: LF: Question about ground impedance at 8.97 KHZ **UPDATE X-Spam-Checker-Version: SpamAssassin 2.63 (2004-01-11) on post.thorcom.com X-Spam-Level: X-Spam-Status: No, hits=0.0 required=5.0 tests=none autolearn=no version=2.63 X-SA-Exim-Scanned: Yes Sender: owner-rsgb_lf_group@blacksheep.org Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group X-SA-Exim-Rcpt-To: rs_out_1@blacksheep.org X-SA-Exim-Scanned: No; SAEximRunCond expanded to false x-aol-global-disposition: G X-AOL-VSS-INFO: 5400.1158/56825 X-AOL-VSS-CODE: clean x-aol-sid: 3039ac1d40824bafebc0162d X-AOL-IP: 193.82.116.20 X-Mailer: Unknown (No Version) ------_=_NextPart_001_01CACED1.85AE55BD Content-Type: text/plain; charset="iso-8859-1" Content-Transfer-Encoding: quoted-printable Hello Paul,=20 =20 Addition: If your C is 340pF and you want to resonate at 8,97kHz, your 545= mH coil is to small! You will need L =3D 926mH! =20 GL, Stefan/DK7FC ________________________________ Von: owner-rsgb_lf_group@blacksheep.org im Auftrag von Paul A. Cianciolo Gesendet: So 28.03.2010 20:27 An: rsgb_lf_group@blacksheep.org Betreff: RE: LF: Question about ground impedance at 8.97 KHZ **UPDATE Hello Stefan, =20 Thank you for the response. I hope to increase the "C" with top wires? =20 The coil I have calculated is very large as you say.=20 Using one of Reg Edwards programs, it appears that a coil 1.2 meters tall,= .6 meters in diameter, using #21 wire, .76 MM dia would result in a 545= mHy inductor. It would take 1500 turns, have a dc res. of 110 ohms and consist of 9300'= of wire for a total of 23 lbs of copper. I chose #21 because of the its= larger than the .46 MM you uses and hopefully would yield a higher "Q" and because I found a 50 LBs spool in possession already helps also. :>)= The predicted "Q" of the inductor is 300. =20 I have to read more about tophat/wires at 9 KHz, but anything that would= reduce the size of the coil would be helpful. =20 PauLC W1VLF =20 =20 =20 =20 =20 =20 -----Original Message----- From: Stefan Sch=E4fer [mailto:owner-rsgb_lf_group@blacksheep.org]On Behal= f Of Stefan Sch=E4fer Sent: Saturday, March 27, 2010 7:23 PM To: rsgb_lf_group@blacksheep.org Subject: AW: LF: Question about ground impedance at 8.97 KHZ **UPDATE Paul, the values you measured seem to be realistic for me. Especially= the measured antenna C does not really differ very much between 137kHz an= d 9 kHz. It is a good value that allows you to dimension your needed L. Th= e needed L is nearly independent from the earth losses. I generally recomm= end a variometer part of 1...5% of the fixed L to compensate all effects= that influence the antenna C. But think about if it is possible to increa= se the antenna C instead of building a very huge coil that causes further= losses. =20 Good luck and have fun with building up! :-) =20 73, Stefan/DK7FC ________________________________ Von: owner-rsgb_lf_group@blacksheep.org im Auftrag von Paul A. Ciancio= lo Gesendet: Sa 27.03.2010 22:01 An: rsgb_lf_group@blacksheep.org Betreff: RE: LF: Question about ground impedance at 8.97 KHZ **UPDATE =20 =20 Hello Folks, =20 Thank you for all the help with measuring my antenna impedance. =20 Let me explain further what I was using to measure with and then add= some updates. The homebrew bridge I was using was built as the one in the following= link. The diagram at the very bottom of the page is the schematic I used. http://www.dxzone.com/cgi-bin/dir/jump2.cgi?ID=3D2285 =20 This really my first venture into things LF and I had really no idea= of what to expect for numbers After posting my results here, and talking to W1VD, he forwarded me a= link to Alan and Finbar's bridge experiments here http://www.alan.melia.btinternet.co.uk/aelossbr.htm =20 Basically I duplicated that design, making sure that the transformer= had 100 mHy of inductance to work at 10 KHz. Sure enough the bridge worked, and balance with my antenna, but would= not balance with my antenna simulator load. =20 The simulated load is 2 X 390 ohm .1% resistors in series with a 500= pf silver mica. =20 Reading on Alan talks about stray capacitance. =20 "The problem with the usual trifilar wound transformer is that if driv= en from an unbalanced source the secondary suffers unbalanced strays to gr= ound. This would mean that if you were to swap the components on the arms= of the bridge the balance would be different" =20 With that in mind I built another transformer to balance the drive to= the bridge. After doing this the bridge will now balance with the simula= ted load and the antenna. See the following numbers for results: =20 Measurments were taken 10Khz The "R" and "C" "known" side of the bridge were then measure measured =20 Sim load =3D 780 Ohms and 507 PF on LCR meter =20 Sim load =3D 940 Ohms and 460 pf on the bridge. =20 =20 Antenna =3D 1111 Ohms and 330 PF on bridge =20 Antenna also measured at 137 KHz =20 Antenna =3D 85 ohms and 340 pf @137 Khz. =20 =20 I think these are more in line with what I should be reading???? =20 What do you folks think? =20 Thank you to everyone who responded to this post and helping me get st= arted. =20 =20 PauL C W1VLF =20 =20 =20 =20 =20 =20 =20 =20 =20 =20 =20 =20 -----Original Message----- From: owner-rsgb_lf_group@blacksheep.org [mailto:owner-rsgb_lf_group@blacksheep.org]On Behalf Of Johan H. Bodin Sent: Friday, March 26, 2010 4:32 PM To: rsgb_lf_group@blacksheep.org Subject: Re: LF: Question about ground impedance at 8.97 KHZ Stefan. =20 =20 Hi Paul, =20 it sounds like your impedance bridge is measuring the absolute impedan= ce (that is Z =3D (R^2 + X^2)^0.5 where R is the real part, resistance,= and X is the imaginary part, reactance). R is probably a 10 to a few hundred ohms, most of it is ground resistance - it can be neglected - the majo= r part of your impedance is the capacitive reactance of the antenna (Xc)= . At 9 kHz, where C =3D 1/(2*Pi*9000*Xc), 70 kOhms means 253pF which is= in the ballpark for your 170' wire (about 5pF/m). =20 73 Johan SM6LKM =20 ---- =20 Paul A. Cianciolo wrote: > > Hello All, > > Below is a quote from the Stefan's web page concerning his latest "D= reamers Band" DX contact Congratulations again Stefan. >>From this information alone is it possible to calculate or know the= antenna system impedance. > > > > > "100m Vertical wire antenna, coil/antenna voltage was abt 15kV rms,= average antenna current about 480mA, giving up to 1,7mW ERP. Applied powe= r was up to 250W." > > Pertaining to the coil "Technical and mechanical data: L=3D553mH, Q= =3D82, R(DC)=3D283 Ohm; 0,4mm diameter enameled copper wire, about 1200 tu= rns! Average diameter 0,55m, height abt 0,5m. So, about 2000m wire! :-)" > > > > I have built a small impedance bridge that operates at 10 KHZ and sh= ows my sloping 170' wire as 70K Ohms. I can also see approx 500 PF that ca= n be nulled out using the bridge? > > Can the 70K value possibly be correct? (3) 6' ground rods about 6'= apart are the ground... plus the electrical ground of the house. > > I am hoping to attempt a local transmission on 9KHZ > > Any information would be helpful. > > Thank you > > Paul > > W1VLF > > > > > =20 =20 =20 ------_=_NextPart_001_01CACED1.85AE55BD Content-Type: application/ms-tnef; name="winmail.dat" Content-Transfer-Encoding: base64 eJ8+IgMXAQaQCAAEAAAAAAABAAEAAQeQBgAIAAAA5AQAAAAAAADoAAEIgAcAGAAAAElQTS5NaWNy b3NvZnQgTWFpbC5Ob3RlADEIAQ2ABAACAAAAAgACAAEEgAEAPwAAAEFXOiBMRjogUXVlc3Rpb24g YWJvdXQgZ3JvdW5kIGltcGVkYW5jZSBhdCA4Ljk3IEtIWiAgICoqVVBEQVRFAFUTAQWAAwAOAAAA 2gcDAB0AAQAwABQAAQBHAQEggAMADgAAANoHAwAdAAEAMwACAAEAOAEBCYABACEAAABGMjRENDkx NTIwQkJEQTQxQTRGQzg1MDJCMkU4NDA3MAAcBwEDkAYABCoAADgAAAADADYAAAAAAEAAOQBzFHwl 0c7KAR4APQABAAAABQAAAEFXOiAAAAAAAgFHAAEAAAAyAAAAYz1ERTthPSA7cD1IU1Q7bD1GSUxF LVNFUlZFUi1ILTEwMDMyODIzNTEwMVotMjI1NQAAAB4ASQABAAAAPwAAAFJFOiBMRjogUXVlc3Rp b24gYWJvdXQgZ3JvdW5kIGltcGVkYW5jZSBhdCA4Ljk3IEtIWiAgICoqVVBEQVRFAABAAE4AAMRa 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