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Date: Wed, 17 Mar 2010 12:11:48 +0100
Message-ID: <38A51B74B884D74083D7950AD0DD85E82A1B66@File-Server-HST.hst.e-technik.tu-darmstadt.de>
Thread-Topic: TA, 300m and new PA?
Thread-Index: AcrFt578v8TghsEfS0uW3zHNwiKmFQABJAEl
References: <Pine.LNX.3.95.1100316221541.251A-100000@noname.nodomain.nowhere> <4BA0A501.5050506@abelian.org>
From: =?iso-8859-1?Q?Stefan_Sch=E4fer?= <schaefer@hst.tu-darmstadt.de>
To: <rsgb_lf_group@blacksheep.org>
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Subject: VLF: TA, 300m and new PA?
Sender: owner-rsgb_lf_group@blacksheep.org
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Reply-To: rsgb_lf_group@blacksheep.org


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Paul, LF,=20
=20
So, if we have the approx formula for VLF propagation and know the range=
 of the noise floor at 8,97kHz, then what would be the TX power i have to=
 apply to a 300m vertical to reach Canada/USA, if there would be some well=
 equipped stations?
You know the details of my antenna and if it is enlarged to 300m, it will=
 be approx: C=3D 1750pF, R(coil, DC)=3D100 Ohm, R(other losses)~400 Ohm,=
 =3D> antenna efficiency at 8,97kHz will be 0,0064%. In this case the limi=
t will not be the antenna voltage but the maximum available power, that is=
 abt 600W. Would that be enough? ;-)
=20
BTW, yesterday i got the idea to built a second PA (to have one in reserve=
 and to:) to get a better operation of the generator: In the moment the PA=
 works on 13,8V that is given bei a SMPS. If the carrier starts there is=
 a power shift of 100% at since the SMPS always takes the needed power fro=
m the generator (even if the 230V droppes to 80V), the fuel/speed regulati=
on becomes unstable. I often noticed a longer drive swing that can take up=
 to one minute (depending on the power and parallel switched batteries).=
 That would become a problem if i really want to take the maximum power th=
e generator gives!
So, if i directly rectify the 230V (with a 300W halogen lamp in series. Th=
e lamp will be short cut by a relay if the voltage across the C is >280V)=
 and apply a big C (i have some 350V/6000=B5F Elkos) and built a class D=
 PA that handles the 350V DC (i plan to use 2x STP10NK80Z FETs) i achieve=
 the maximum power the generator will give. The power regulation will be=
 optimal since the power decreases ~1/U^2. Even the small SMPS of the Note=
book will be no problem since it covers a wide input voltage range. When=
 using a small 230V/10VA transformer to generate 15V DC for the driver and=
 use optical components for keying and using the given isolating output tr=
ansformer of the PA, there is no danger to get a shock unless i do not tou=
ch the PA during operation. The FETs are protected from overload power by=
 the generator and since they have integrated Z diodes, they will not be=
 damaged by eventual voltage spikes... ;-)=20
=20
73, Stefan=20

________________________________

Von: owner-rsgb_lf_group@blacksheep.org im Auftrag von Paul Nicholson
Gesendet: Mi 17.03.2010 10:46
An: rsgb_lf_group@blacksheep.org
Betreff: Re: LF: Ionospheric VLF propagation



Alexander wrote:
 > Certanly exponential factor exp(-r/a) should be present.
 > I mentioned this before.

Yes you did!  I am following your lead with this 1/sqrt(r)
thing and the exponential factor.  And it is working - it is
giving the right answer for Stefan's signal!

3dB per 1000km (daytime) is mentioned in some literature but
I have to follow that up.    Assuming that, we have the
estimate for daytime flux density at range r:-

    B =3D sqrt( 9.5e-21 * ERP/r) * exp( -r/2.9e6)

 > But this should be calculated. At the earth bondary one can
 > use Leontovich bondary condition

Yes.

 > But what to do with ionosphere boundary... To neglect dissipation
 > in ionosphere looks not reasonable.

Yes too.  The ionosphere boundary is more complicated.  There are
two values for the refractive index - attenuation depends on
direction relative to Earth's magnetic field.  The result is
phase and polarisation changes.   I have some references to follow
up here too.   But it is complicated and time consuming.  It
would be nice to just use average figures for day and night
attenuation - surely good enough for 'amateur' work.

 > To solve the problem (rather volumable problem) is nice task
 > for physicist.

The hard work was done, decades ago, and appears to be fairly
well established.  But it is a major job to go through the
literature and pick out what is relevant.  It is a heady mix
of plasma physics, EM theory and ray tracing.  There are one
or two textbooks - one I will order today.
--
Paul Nicholson
--



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