Return-Path: Received: (qmail 80765 invoked from network); 27 Aug 2004 17:22:11 -0000 Received: from unknown (HELO ptb-spamcore01.plus.net) (192.168.71.1) by ptb-mailstore02.plus.net with SMTP; 27 Aug 2004 17:22:11 -0000 Received: from mailnull by ptb-spamcore01.plus.net with spamcore-l-b (Exim 4.32; FreeBSD) id 1C0kW6-000HT5-5B for dave@picks.force9.co.uk; Fri, 27 Aug 2004 18:27:58 +0100 Received: from [192.168.67.3] (helo=ptb-mxcore03.plus.net) by ptb-spamcore01.plus.net with esmtp (Exim 4.32; FreeBSD) id 1C0kW6-000HT2-2Q for dave@picks.force9.co.uk; Fri, 27 Aug 2004 18:27:58 +0100 Received: from post.thorcom.com ([193.82.116.20]) by ptb-mxcore03.plus.net with esmtp (Exim) id 1C0kQT-000C5O-WD for dave@picks.force9.co.uk; Fri, 27 Aug 2004 18:22:10 +0100 Received: from majordom by post.thorcom.com with local (Exim 4.14) id 1C0kQ2-0002Cw-SF for rs_out_1@blacksheep.org; Fri, 27 Aug 2004 18:21:42 +0100 Received: from [193.82.116.30] (helo=relay.thorcom.net) by post.thorcom.com with esmtp (Exim 4.14) id 1C0kQ2-0002Cn-Ab for rsgb_lf_group@blacksheep.org; Fri, 27 Aug 2004 18:21:42 +0100 Received: from c2bapps19.btconnect.com ([193.113.154.35] helo=dswu231.btconnect.com) by relay.thorcom.net with smtp (Exim 4.41) id 1C0kPy-00019F-Bc for rsgb_lf_group@blacksheep.org; Fri, 27 Aug 2004 18:21:42 +0100 Received: from 83Horseshoe (actually host 175.82.35.217.in-addr.arpa) by dswu231 with SMTP-CUST (XT-PP) with ESMTP; Fri, 27 Aug 2004 18:21:31 +0100 From: "Martin G8CIX " To: rsgb_lf_group@blacksheep.org Date: Fri, 27 Aug 2004 18:21:46 +0100 Message-ID: <000001c48c5a$58090d30$6501a8c0@83Horseshoe> MIME-Version: 1.0 X-Priority: 3 (Normal) X-MSMail-Priority: Normal X-Mailer: Microsoft Outlook, Build 10.0.6626 Importance: Normal In-Reply-To: X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2900.2180 X-SPF-Result: relay.thorcom.net: 193.113.154.35 is neither permitted nor denied by domain of btconnect.com X-Spam-Score: 0.3 (/) X-Spam-Report: autolearn=no,HTML_50_60=0.183,HTML_FONTCOLOR_UNKNOWN=0.1,HTML_MESSAGE=0.001 Subject: LF: RE: RE: Re: Gas for balloons Content-Type: text/html; charset=windows-1252 X-Spam-Checker-Version: SpamAssassin 2.63 (2004-01-11) on post.thorcom.com X-Spam-Status: No, hits=0.3 required=5.0 tests=HTML_50_60, HTML_FONTCOLOR_UNKNOWN,HTML_MESSAGE autolearn=no version=2.63 X-SA-Exim-Scanned: Yes Sender: owner-rsgb_lf_group@blacksheep.org Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group X-SA-Exim-Rcpt-To: rs_out_1@blacksheep.org X-SA-Exim-Scanned: No; SAEximRunCond expanded to false X-Spam-Filtered: by PlusNet SpamCORE (v3.00) Content-transfer-encoding: 8bit

Jim

If you have read the article How Helium Balloons Work, then you know that helium has a lifting force of 1 gram per liter. So if you have a balloon that contains 5 liters of helium, the balloon can lift 5 grams.

A normal balloon at an amusement park might be 30 centimeters (about 1 foot) in diameter. To determine how many liters of helium a sphere can hold, the equation is 4/3*pi*r*r*r. The radius of a 30-centimeter-diameter balloon is 15 centimeters, so:

4/3 * pi * 15 * 15 * 15 = 14,137 cubic centimeters = 14 liters

So a normal amusement park balloon can lift about 14 grams, assuming that the weight of the balloon itself and the string is negligible.

If you weigh 50 kilograms (about 110 pounds), then you weigh 50,000 grams. Divide your 50,000 grams by the 14 grams per balloon and you find that you need 3,571.42 balloons to lift your weight. You might want to add 500 more if you actually would like to rise at a reasonable rate. So you need roughly 4,000 balloons to lift yourself if you weigh 50 kilograms, and you can adjust that number according to your weight.

Let's say that instead of going to the amusement park, you go to an army surplus store and buy one 3-meter (about 10-foot) balloon. It can hold:

4/3 * pi * 150 * 150 * 150 = 14,137,000 cubic centimeters = 14,137 liters

It would only take four of those to give you the same lift.

One balloon that is 30 meters (about 100 feet) in diameter displaces 14,137,000 liters, so it can lift 14,000 kilograms (about 31,000 pounds) -- this is roughly the size of a large blimp.

 

 

Regards

 

Martin Maynard

 

-----Original Message-----
From: owner-rsgb_lf_group@blacksheep.org [mailto:owner-rsgb_lf_group@blacksheep.org] On Behalf Of James Moritz
Sent:
27 August 2004 10:49
To: rsgb_lf_group@blacksheep.org
Subject: LF: RE: Re: Gas for balloons

 

Dear David, LF group,

 

From what I remember of chemistry at school,  1mole of gas at room temp and atmospheric pressure occupies 22.4 litres of volume, and 1 mole of He weighs about 4g, whilst 1 mole of H2 weighs 2g. So a cubic metre of helium will weigh about 180g, whilst the same amount of hydrogen about 90g. Air is mostly nitrogen N2 at 28g/mole, so the air displaced weighs about 1250g. So the increased buoyancy of the hydrogen will only give 90g, about 7%, extra lift – ignoring the weight of the actual balloon itself.

 

What I would like to know is - what is a good source for the balloons?

 

Cheers, Jim Moritz

73 de M0BMU