Return-Path: Received: (qmail 25449 invoked from network); 11 Apr 2001 09:04:22 -0000 Received: from unknown (HELO murphys-inbound.servers.plus.net) (212.159.14.225) by 10.226.25.101 with SMTP; 11 Apr 2001 09:04:22 -0000 Content-Type: text/plain; charset=iso-8859-1; format=flowed Content-Transfer-Encoding: 8bit Received: (qmail 6683 invoked from network); 11 Apr 2001 09:04:14 -0000 X-Priority: 3 X-MSMail-Priority: Normal Received: from unknown (HELO post.thorcom.com) (212.172.148.70) by murphys with SMTP; 11 Apr 2001 09:04:14 -0000 Received: from majordom by post.thorcom.com with local (Exim 3.16 #2) id 14nGRW-0007KX-00 for rsgb_lf_group-outgoing@blacksheep.org; Wed, 11 Apr 2001 09:57:38 +0100 X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 Received: from tele-post-20.mail.demon.net ([194.217.242.20]) by post.thorcom.com with esmtp (Exim 3.16 #2) id 14nGRR-0007KR-00 for rsgb_lf_group@blacksheep.org; Wed, 11 Apr 2001 09:57:33 +0100 Received: from telemetry.demon.co.uk ([194.222.19.114]) by tele-post-20.mail.demon.net with smtp (Exim 2.12 #2) id 14nGR1-000021-0K for rsgb_lf_group@blacksheep.org; Wed, 11 Apr 2001 08:57:07 +0000 Message-ID: Date: Wed, 11 Apr 2001 09:05:05 +0100 To: "RSGB LF Group" From: "Tom Boucher" Subject: LF: Technical (but not very) - Loops MIME-Version: 1.0 X-Mailer: Turnpike Version 3.03a Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group Sender: Dear all Contemplating making one of Peter's 'Superloop' antennas and find that I have aprox. 100 metres of Crawley Litz in stock. Now Peter's article sez I have to cut 11 x 16.3m lengths of wire = 180 metres of wire, so I haven't got enough. But before I go rushing off to Derek to buy some more, a simple sum casts some doubt on Peter's calculations. His loop has 2 metre sides and it has 4 sides so one turn equals 8 metres, not 16m, in which case I have enough Litz! Am I missing something, or should I go back to school for a refresher course in sums? 73, Tom G3OLB