Return-Path: Received: (qmail 15291 invoked from network); 7 Jun 2000 11:37:09 -0000 Received: from unknown (HELO post.thorcom.com) (212.172.148.70) by bells.core.plus.net.uk with SMTP; 7 Jun 2000 11:37:09 -0000 Received: from majordom by post.thorcom.com with local (Exim 3.02 #1) id 12zejG-00071l-00 for rsgb_lf_group-outgoing@blacksheep.org; Wed, 07 Jun 2000 13:14:38 +0100 Received: from helios.herts.ac.uk ([147.197.200.2]) by post.thorcom.com with esmtp (Exim 3.02 #1) id 12zejF-00071g-00 for rsgb_lf_group@blacksheep.org; Wed, 07 Jun 2000 13:14:37 +0100 X-Priority: 3 X-MSMail-Priority: Normal Received: from [147.197.200.44] (helo=gemini) by helios.herts.ac.uk with esmtp (Exim 3.11 #1) id 12zdzp-00013g-00 for rsgb_lf_group@blacksheep.org; Wed, 07 Jun 2000 12:27:41 +0100 Message-ID: <2539.200006071127@gemini> X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 From: "James Moritz" Organization: University of Hertfordshire To: rsgb_lf_group@blacksheep.org Date: Wed, 7 Jun 2000 12:34:49 +0000 MIME-Version: 1.0 Content-Type: text/plain; charset=US-ASCII; format=flowed Content-Transfer-Encoding: 8bit Subject: Re: LF: Formula In-reply-to: <4.2.0.58.20000607100135.00966c00@mail.pncl.co.uk> X-Mailer: Pegasus Mail for Win32 (v3.11) Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group Sender: Date sent: Wed, 07 Jun 2000 10:25:14 +0100 To: rsgb_lf_group@blacksheep.org From: Walter Blanchard Subject: LF: Formula Send reply to: rsgb_lf_group@blacksheep.org > I found the following in an article recently. > > Quote: > > "The intensity E (known as the field strength) of a transmission > at a distance D from a source transmitting P watts of RF power via > a half-wave dipole in a free, unobstructed space, can be estimated > using the formula: > > E=(7*sqrt (P))/D. Dear Walter & Group, If the propagating wave is a transverse electromagnetic wave (which it will be a reasonable distance from the antenna, in 'free space'), the electric (E volts/m) and magnetic (H amps/m) fields are proportional; E/H = 120pi ohms. This 'free space wave impedance' is about 377ohms and is a constant provided the permeability and permittivity of the medium is the same as a vacuum, or air is near enough. This comes about ultimately from the definitions of volts and amps. E times H has the dimensions of watts/sq. metre and so is called the power density, S. A bit of algebra gives you power density S = (Esquared)/120pi (compare with P = (Vsquared)/R), so measuring E is effectively also a measure of power density, and also a measure of H. Rearranging this gives E = sqrt(120piS) If the antenna in free space radiated equally in all directions, (ie. an 'isotropic radiator'), at a distance d the radiated power P would be evenly distributed over the surface of a sphere of radius d. the surface of the sphere would have an area 4pi(d squared), so power density would be S = P / 4pi(d squared). Putting this value of power density into the equation for E gives E= sqrt (30P/(d squared), or E= 5.477 sqrt(P)/d. This applies to an isotropic radiator, but all real antennas have a directional pattern, and so in the direction of their maximum radiation, the power density is increased by a factor D (note not d, the distance), the directivity or directional gain. This makes E = 5.477 sqrt (PD)/d. The value of D depends on the geometry and voltage and current distribution of the antenna. It's quite complex to work out, but can be done for simple antennas - refer to an antenna text book for details! - it can be calculated by programs such as EZNEC for more complicated antennas. For a half wave dipole it is 1.64, for a short monopole it is 3. Putting D = 1.64 into the formula gives E = 7.01 sqrt (P) / d for a half wave dipole, E = 9.49 sqrt (P) / d for a short monopole. Hope that is some help, Cheers, Jim Moritz 73 de M0BMU