Return-Path: Received: (qmail 2654 invoked from network); 27 Aug 1999 12:49:33 -0000 Received: from magnus.plus.net.uk (HELO magnus.force9.net) (195.166.128.27) by murphys.force9.net with SMTP; 27 Aug 1999 12:49:33 -0000 Received: (qmail 7862 invoked from network); 27 Aug 1999 12:47:20 -0000 Content-Transfer-Encoding: 8bit Received: from unknown (HELO post.thorcom.com) (212.172.148.70) by magnus.plus.net.uk with SMTP; 27 Aug 1999 12:47:20 -0000 Received: from majordom by post.thorcom.com with local (Exim 3.02 #1) id 11KLEb-0002ob-00 for rsgb_lf_group-outgoing@blacksheep.org; Fri, 27 Aug 1999 13:35:57 +0100 X-Priority: 3 X-MSMail-Priority: Normal Received: from mailserv.cc.kuleuven.ac.be ([134.58.8.44]) by post.thorcom.com with esmtp (Exim 3.02 #1) id 11KLEa-0002oW-00 for rsgb_lf_group@blacksheep.org; Fri, 27 Aug 1999 13:35:56 +0100 Received: from LCBD15.fys.kuleuven.ac.be (LCBD15.fys.kuleuven.ac.be [134.58.80.15]) by mailserv.cc.kuleuven.ac.be (8.9.0/8.9.0) with SMTP id OAA17043 for ; Fri, 27 Aug 1999 14:42:09 +0200 Message-ID: <3.0.1.16.19990827143645.268f4bda@mail.cc.kuleuven.ac.be> X-MimeOLE: Produced By Microsoft MimeOLE V6.00.2800.1106 X-Sender: pb623250@mail.cc.kuleuven.ac.be X-Mailer: Windows Eudora Pro Version 3.0.1 (16) Date: Fri, 27 Aug 1999 14:36:45 To: rsgb_lf_group@blacksheep.org From: "Rik Strobbe" Subject: LF: Multiple Tuned Vertical : simple calculations In-reply-to: <002301bef040$442b1580$aff4f482@win95.swipnet.se> MIME-Version: 1.0 Content-Type: text/plain; charset=us-ascii; format=flowed Precedence: bulk Reply-To: rsgb_lf_group@blacksheep.org X-Listname: rsgb_lf_group Sender: Doing some simple maths on a the simple model of a (lossless) double tuned vertical I got this result : 1. Starting from a (lossless) single tuned vertical you get +------+ | | +-+ ----- where L = loading coil L | | ----- C C = antenna capacitance | | | R = radiation resistance +-+ +-+ R Z = antenna impedance | | | -----+ +-+ Z = | ------------+ If the reactance L (XL) cancels the reactance of C (XC) the antenna impeadnce Z equals the radiation resistance R so wL = 1/(wC) (where w = 2 x Pi x frequency) 2. 'Upgrade' the antenna to a double tuned vertical : +------+--------+ | | | +-+ ----- +-+ L' | | ----- C | | L' | | | | | +-+ +-+ R +-+ | | | | -----+ +-+ | Z = | | ------------+--------+ Instead of 1 inductor L we now have 2 inductors L' of the double value (2L) Since the values of C and R are unchanged is wL' = 2/(wC) Further XC = 1/(jwC) = -j/(wC) (where j = square root of -1) and XL' = jwL' = j2/(wC) = -2XC Calculating Z gives Z = XL + (XL x (XC + R)) / (XL + XC + R) -> extract XL Z = XL x (1 + (XC + R) / (XL + XC + R)) -> replace XL by -2XC Z = -2XC x (1 + (XC + R) / (-2XC + XC +R)) -> -2XC + XC = -XC Z = -2XC x (1 + (XC + R) / (R - XC)) -> equalize to (R-XC) Z = -2XC x (R - XC + XC + R) / (R - XC) -> R - XC + XC + R = 2R Z = -2XC x (2R) / (R - XC) for practical antennas will XC be in the range of 500 to 5000 Ohm while R will be well below 1 Ohm so we can say that R - XC = -XC Z = -2XC x (2R) / (-XC) -> -2XC / -XC = 2 Z = 4R So the antenna impedance of a resonant double tuned vertical will be 4 times the impedance of a single tuned vertical. But what to do with the 'loss resistance' (RL) in the real world ? Assume a simple model where both tuned sections share the same ground-system. In that case RL would be in series with R and this would mean that a double tuned vertical would not only quadruple the radiation resistance but also the loss resistance, resulting in an unchanged ratio between radiation resistance and loss resistance. >From the above I expect that a multiple-tuned vertical will only outperform a simple vertical if each tuned section has at least its own independent groundsystem. This would also mean that you need a certain distance between the tuned sections in order to get these independent grounds. Comments welcome ... 73, Rik So Rik Strobbe ON7YD rik.strobbe@fys.kuleuven.ac.be Villadreef 14 B-3128 Baal BELGIUM (JO20IX)